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horsena [70]
2 years ago
7

46. An olympic athlete has just completed a four mile run. His average time was 6 minutes per mile. If he ran the first and last

mile in 5 minutes, and the other 2 were the same time as each other, what was the average time for the 2 miles in the middle
Mathematics
1 answer:
uranmaximum [27]2 years ago
4 0

Answer:

7 minutes

Step-by-step explanation:

average time = 6 minutes per mile

sum = average * count = 6 minutes / mile * 4 miles = 24 minutes

first + last mile = 5 + 5 = 10 minutes

first + second + third + last mile = sum = 24 minutes

second + third = sum - first - last = 24 - 5 - 5 = 24 - 10 = 14 minutes

average of 2 miles in the middle = sum / count = 14 minutes / 2 = 7 minutes

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Answer:
8 5/7
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stepan [7]

Answer:

Step-by-step explanation:

Given that a solution containing 12% alcohol is to be mixed with a solution containing 4% alcohol to make 20 gallons of solution containing 9% alcohol.

Let x gallons of 12% alcohol be mixed with y gallons of 4% alcohol.

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b) Two equations are

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c) This is of the form Ax = B

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7 0
3 years ago
Al principio Eduardo y Adrián tenían el mismo número de dulces. Eduardo le dio a Adrián la mitad de los dulces que tenía. Despué
Dennis_Churaev [7]

Answer:

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Step-by-step explanation:

Dado que al principio Eduardo y Adrián tenían el mismo número de dulces, y Eduardo le dio a Adrián la mitad de los dulces que tenía, y después, Adrián le dio a Eduardo la mitad de los dulces que tenía él en ese momento, así que a Adrián le quedaron 12 dulces, para determinar cuántos dulces tenía Eduardo al final se debe realizar el siguiente cálculo:

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Así, al final, Eduardo tenía 20 dulces.

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3 years ago
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Answer:

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7 0
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