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3 years ago

Help me out here and show work please

Mathematics

1 answer:

marusya05 [52]3 years ago

4 0

Answer:

x = 3, x = 15, x = 12, x = 1

Hope this helps :)

Step-by-step explanation:

1.) 4x - 1 = 2x + 5

+1 +1

4x = 2x + 6

-2x -2x

2x = 6

x = 3

2.) 3x - 5 = 2x + 10

+5 +5

3x = 2x + 15

-2x -2x

x = 15

3.) 4x + 2 + 30 = 8 + 6x

4x + 32 = 8 + 6x

-8 -8

4x + 24 = 6x

-4x -4x

24 = 2x

x = 12

4.) 4( x - 1) + 5 = 2x + 3

4x -4 + 5 = 2x + 3

4x + 1 = 2x + 3

-1 -1

4x = 2x + 2

-2x -2x

2x = 2

x = 1

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Juan rents a car for $29.00 a week. He pays $17.00 per week for the insurance and spends $13.50 weekly on gas. What will his cos

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$29+$17+$13 = $59 weekly spending
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2 years ago

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Slips of paper numbered 1 to 15 are placed in a box. A slip of paper is drawn at random. What is the probability that the number

monitta

Given:

Slips of paper numbered 1 to 15 are placed in a box.

To find:

The probability that the number picked is either a multiple of 5 or an odd number.

Solution:

We have,

Total outcomes = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15

No. of total outcomes = 15

Multiple of 5 are 5, 10, 15.

Odd numbers are 1, 3, 5, 7, 9, 11, 13, 15.

Number that are either a multiple of 5 or an odd number are 1, 3, 5, 7, 9, 10, 11, 13, 15.

No. of favorable outcomes = 9

We know that,

$\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}$

$\text{Probability}=\dfrac{9}{15}$

$\text{Probability}=\dfrac{3}{5}$

$\text{Probability}=0.6$

Therefore, the probability that the number picked is either a multiple of 5 or an odd number is 0.6.

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2 years ago

You deposit 2000 in account A, which pays 2.25% annual interest compounded monthly. You deposit another 2000 in account b, which

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To model this situation, we are going to use the compound interest formula: $A=P(1+ \frac{r}{n} )^{nt}$
where
$A$ is the final amount after $t$ years
$P$ is the initial deposit
$r$ is the interest rate in decimal form
$n$ is the number of times the interest is compounded per year
$t$ is the time in years

For account A:
We know for our problem that $P=2000$ and $r= \frac{2.25}{100} =0.0225$ . Since the interest is compounded monthly, it is compounded 12 times per year; therefore, $n=12$ . Lets replace those values in our formula:
$A=2000(1+ \frac{0.0225}{12} )^{12t}$

For account B:
$P=2000$ , $r= \frac{3}{100} =0.03$ , $n=12$ . Lest replace those values in our formula:
$A=2000(1+ \frac{0.03}{12} )^{12t}$

Since we want to find the time, $t$ , <span>when the sum of the balance in both accounts is at least 5000, we need to add both accounts and set that sum equal to 5000:
</span> $2000(1+ \frac{0.0225}{12} )^{12t}+2000(1+ \frac{0.03}{12} )^{12t}=5000$

Now that we have our equation, we just need to solve for $t$ :
$2000[(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}]=5000$
$(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}= \frac{5000} {2000}$
$(1.001875)^{12t}+(1.0025 )^{12t}= \frac{5}
{2}$
$ln(1.001875)^{12t}+ln(1.0025 )^{12t}=ln( \frac{5} {2})$
$12tln(1.001875)+12tln(1.0025 )=ln( \frac{5} {2})$
$t[12ln(1.001875)+12ln(1.0025 )]=ln( \frac{5} {2})$
$t= \frac{ln( \frac{5}{2} )}{12ln(1.001875)+12ln(1.0025 )}$
$17.47$

We can conclude that after 17.47 years <span>the sum of the balance in both accounts will be at least 5000.</span>

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3 years ago

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2 years ago

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FIND (-8/3)+(-1/4)+(-11/6)+3/8-3

emmainna [20.7K]

Answer:

-7 3/8

Step-by-step explanation:

The least common denominator of 3, 4, 6, and 8 is 24; converting all of our fractions to that denominator and solving, we have

$-\frac{8}{3}+\left(-\frac{1}{4}\right)+\left(-\frac{11}{6}\right)+\frac{3}{8}-3\\=-\frac{64}{24}+\left(-\frac{6}{24}\right)+\left(-\frac{44}{24}\right)+\frac{9}{24}-3\\\\=\frac{-64+(-6)+(-44)+9}{24} -3\\\\=\frac{-70+(-44)+9}{24} -3\\\\=\frac{-114+9}{24} -3\\\\=\frac{-105}{24}-3 \\\\=\frac{-35}{8}-3\\ \\=-4\frac{3}{8}-3\\\\=-7\frac{3}{8}$

So our solution is -7 3/8

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3 years ago