Given:
Mean, μ = 196
Std. dev., σ = 22
A sample size of 50 (> 30) is large enough to provide meaningful data.
The random variable is x = 200.
The z-score is
z = (x - μ)/σ = (200 - 196)/22 = 0.1818
From normal distribution tables, obtain
Prob(X < 200) = 0.572 = 57.2%
Answer: 57.2%
I believe he should add 2ft to the height of the tree as well
I can’t do it rn so just dm me later
(0,16)
because the number on the x axis is 0 and the number on the y axis is 16
have a nice day and good luck with the rest of your homework!
Answer:
C −2a^3+9a^2+45a+6ab^2+18b^2
Step-by-step explanation:
(a+3) ( −2a^2+15a+6b^2)
Distribute the a to the large term in parentheses and the 3 to the large term in parentheses
a ( −2a^2+15a+6b^2)+3 ( −2a^2+15a+6b^2)
−2a^3+15a^2+6ab^2 −6a^2+45a+18b^2
Combine like terms
−2a^3+15a^2−6a^2+6ab^2 +45a+18b^2
-2 a^3 + 9 a^2 + 6 a b^2 + 45 a + 18 b^2
