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2 years ago

a cafeteria used 128.5 kilograms of beans to make 5 batches of chili. what quantity of beans went into each batch

Mathematics

1 answer:

nikdorinn [45]2 years ago

7 0

Answer:25.7

Step-by-step explanation:

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Which fraction would make this equation true 5×?=6 1/4

Blizzard [7]

The answer is 1 1/4.

4 0

2 years ago

Mark is planning to run in a 10-km race he will have to run 1 4/5 km uphill, 2 7/10 km downhill, and the rest of the race on lev

777dan777 [17]

<span>Uphill distance = 1 4/5 = 9/5 = 18/10 km Downhill Distance = 2 7/10 = 27/10 km Total Uphill and Downhill = 18/10 + 27/10 = 45/10 = 4.5 km Hence total level ground = Total race km - (Uphill + Downhill) =10 - 4.5 = 5.5 km Hence the answer is 5.5 km.</span>

7 0

3 years ago

The number of books borrowed from a library each week follows a normal distribution. When a sample is taken for several weeks, t

Marat540 [252]

$\mathbb P(X>250)=\mathbb P\left(\dfrac{X-190}{30}>\dfrac{250-190}{30}\right)=\mathbb P(Z>2)\approx0.0228$

Or, if you're familiar with the empirical rule and the basic properties of the normal distribution, you can use the fact that approximately $95/%$ of the distribution lies within two standard deviations of the mean, or

$\mathbb P(|Z|$

which means about $5\%$ of the distribution lies outside this interval, or

$\mathbb P((-22))\approx0.05$

Because the distribution is symmetric, you have

$\mathbb P(-22)$
$\implies \mathbb P((-22))=\mathbb P(-22)=2\mathbb P(Z>2)\approx0.05$
$\implies \mathbb P(Z>2)\approx 0.025$

8 0

3 years ago

Read 2 more answers

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

2 years ago

Troy Ulman received his annual savings account statement, showing $78.75 in interest. If his savings account balance was $2,100

Naya [18.7K]

Answer is 3.75%

3.75% = 0.0375

0.0375 + $2,100 = <span>$78.75</span>

4 0

3 years ago