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2 years ago

A family of 8 people is entitled to a ratio of 6400 grams of sugar. What will be the sugar ratio for a family of 10 people?

Mathematics

2 answers:

Art [367]2 years ago

8 0

Answer:

Hey There!

Let's solve...

We need to find out the quantity of sugar of 1 person first...

$6400g = 8 \: people \\ \\ \therefore \: 1 \: people = \frac{6400}{8} \\ \\ simplify \\ \\ \frac{ \cancel{6400 }^{800} }{ \cancel{8}} \\ \\ = 800g \: or \: 0.8kg$

Now let's find out sugar for 10 people

$= 800 \times 10 = 8000g \: or \: 8kg$

<h2>I hope it is helpful to you.. </h2><h3>Cheers!_________</h3>

ryzh [129]2 years ago

7 0

6400/8=800, this leaves 800g of sugar per person.
800*10= 8000
So this family is entitled to 8000g of sugar

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4q=52 wats the answer to this equation

Darya [45]

4q=52

divide by 4 for both sides

4q/4= 52/4

q= 13

Answer : q=13

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3 years ago

Let $a$ and $b$ be nonzero real numbers such that

algol [13]

<h3>Answer: -7/2</h3>

=========================================================

Explanation:

Let's expand out (2 - 7i)(a + bi) using the FOIL rule

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7bi^2

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7b(-1)

(2 - 7i)(a + bi) = 2a + 2bi - 7ai + 7b

(2 - 7i)(a + bi) = (2a+7b) + (2bi-7ai)

(2 - 7i)(a + bi) = (2a+7b) + (2b-7a)i

We're told the result is purely imaginary. What this means is that the real part (2a+7b) is zero, while the imaginary part (2b-7a) is nonzero. If both are zero, then we have 0+0i = 0 which is purely real.

For example, the complex numbers 0-7i and 0+2i are purely imaginary.

Let's use the fact that 2a+7b must be zero to do the following steps:

2a+7b = 0

2a = -7b

a = -7b/2

a/b = -7/2 which is the final answer

We must check to see if 2b-7a is nonzero

2b - 7a = 2b - 7(-7b/2)

2b - 7a = 2b + 24.5b

2b - 7a = 26.5b

The result is nonzero if and only if b is nonzero. Luckily we're told b is nonzero at the top of the problem. So we don't have any worries that (2b-7a) is zero.

Therefore, (2a+7b) + (2b-7a)i will be purely imaginary with a/b = -7/2

------------------

A concrete example:

Let a = -14 and b = 4

a/b = -14/4 = -7/2

(2-7i)(a+bi) = (2-7i)(-14+4i) = 0 + 106i which is purely imaginary.

I'll let you do the steps in expanding that out using the FOIL rule.

4 0

1 year ago

Breanna wrote a number that is 4 units from 0 on the number line.

Hatshy [7]

The two answers are -4 and 4, because 0-4 is -4 and 0+4 is 4. Hope this helps