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2 years ago

A family of 8 people is entitled to a ratio of 6400 grams of sugar. What will be the sugar ratio for a family of 10 people?

Mathematics

2 answers:

Art [367]2 years ago

8 0

Answer:

Hey There!

Let's solve...

We need to find out the quantity of sugar of 1 person first...

$6400g = 8 \: people \\ \\ \therefore \: 1 \: people = \frac{6400}{8} \\ \\ simplify \\ \\ \frac{ \cancel{6400 }^{800} }{ \cancel{8}} \\ \\ = 800g \: or \: 0.8kg$

Now let's find out sugar for 10 people

$= 800 \times 10 = 8000g \: or \: 8kg$

<h2>I hope it is helpful to you.. </h2><h3>Cheers!_________</h3>

ryzh [129]2 years ago

7 0

6400/8=800, this leaves 800g of sugar per person.
800*10= 8000
So this family is entitled to 8000g of sugar

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2 years ago

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2 years ago

According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e

slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that $p = 0.09$

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

$P(X < 4) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

$P(X \geq 4) = 1 - P(X < 4)$

In which

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225$

$P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827$

$P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082$

$P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982$

Finally

$P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180$

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

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2 years ago

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Zarrin [17]

Answer:

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Will be 100cm as when approximated to tenth

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3 years ago

I need help with this math please

Alexus [3.1K]

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Now that we know the value of one variable, we can take that value and plug it back into one of the original equations and solve for the value of the other variable.

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The solution to this system of equations is (2, 3).

Hope this helps!! :)

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2 years ago

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