(x+3)/2x+5 + (3x-5)/(3x+5)
LCM = ( 2x+5)( 3x+5)
[( x+3)( 3x+5) + ( 3x -5)( 2x+5)]/( 2x+5)( 3x+5)
= (3x^2 + 5x +9 x +15 + 6x^2 + 15x -10x -25)/( 2x+5)( 3x+5)
=( 9 x^2 + 19x -10)/( 2x +5)(3x+5)
A) option
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It is 1/6 or .16 I used Photomath
Answer:
1/(5^12 * 32^3 * 9^15)
Step-by-step explanation:
5^-12 = 1/(5^12)
32^-3 = 1/(32^3)
9^-15 = 1/(9^15)
1/(5^12) * 1/(32^3) * 1/(9^15) = 1/(5^12 * 32^3 * 9^15)
Answer:
Step-by-step explanation:
To find your answer you first have to multiply the numbers that aren’t in parentheses and you multiply 2 and 7 and you get 14 then you don’t have to worry about the x because it is a variable so now add -4 +2. but first we have to turn negative into positive so you add -4 + 8