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2 years ago

PLEASE HURRY I WILL DO ANYTHING (not anything but give brain list)

Mathematics

1 answer:

Sergeeva-Olga [200]2 years ago

4 0

The cost of the sheets is less for the second example, the second example is the better deal.

Consider the first example:

Here, A brand of sheets is on sale for “Buy one get one at 50% off”. If each sheet costs $18.00.

So, the value of the first sheet will be $18,

And since the other sheet is at 50% off .

That is it will be half of the original value

= 50/100 * 18

Therefore, the cost of two sheets

=$18 + $9

= $27.

So, Six sheets will cost

=$27+$27+$27

= $81

Cost of six sheets will be $81

Now, consider the second example

In the second example sheets are 30% off.

So, 30% of 18

= $6.

Subtract that value from 18 and you will get $12.

So, cost of one sheet = $12.

cost of 6 sheet

= $12×6

= $72

In the first example, Six sheets costs $81, while in the second example six sheets cost $72.

Since the cost is less for the second example. So, the second example is the better deal.

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Write a doubles plus one fact for the sum of 7

gladu [14]

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8 0

3 years ago

Read 2 more answers

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$