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Lorico [155]
3 years ago
7

What is the answer to -(7c - 18) - 2c>0

Mathematics
1 answer:
IgorLugansk [536]3 years ago
4 0

Answer:

The answer would be C < 2

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When 2 lines are perpendicular to one another, how many degrees is their angle intersection
serious [3.7K]
90 degrees is the angle at intersection
5 0
3 years ago
Hey hey I need some help with percent change
Neporo4naja [7]

Answer:

\boxed{20 \%}

Step-by-step explanation:

% Increase = Increase/Original value × 100 %

Data:

   Latest selling price = $20

-Original selling price = <u>-  16 </u>

                    Increase = $  4

Calculations:

% increase = 4/20 × 100 % = 20 %

The percent increase is \boxed{20 \%}.

4 0
3 years ago
Read 2 more answers
A cook used all of a two-pound chunk of cheese in making three recipes. Recipe I used one-third as much cheese as Recipe II did,
skelet666 [1.2K]

Answer:

Recipe I uses 10% of the whole chunk of cheese.

Recipe II uses 30% of the whole chunk of cheese.

Recipe II uses 60% of the whole chunk of cheese.

Recipe I uses 0.2 pounds of cheese.

Recipe II uses 0.6 pounds of cheese.

Recipe II uses 1.2 pounds of cheese.

Step-by-step explanation:

Total amount of cheese = 2 pounds

Recipe I used one-third as much cheese as Recipe II did, and Recipe II used one-half as much cheese as Recipe III.

Let the amount of cheese used by recipe I, II and III be x, y and z respectively.

Total amount of cheese = 2 pounds

x + y + z = 2 (eqn 1)

Recipe I used one-third as much cheese as Recipe II did

x = (1/3)y

y = 3x

Recipe II used one-half as much cheese as Recipe III.

y = (1/2)z

z = 2y

z = 2y = 2(3x) = 6x

Substituting all of these into eqn 1

x + y + z = 2

x + 3x + 6x = 2

10x = 2

x = 0.2 pounds of cheese

y = 3x = 0.6 pounds of cheese

z = 6x = 1.2 pounds of cheese.

Recipe I uses (0.2/2) = 10% of the whole chunk of cheese.

Recipe II uses (0.6/2) = 30% of the whole chunk of cheese.

Recipe II uses (1.2/2) = 60% of the whole chunk of cheese.

Hope this Helps!!!

5 0
3 years ago
Simplify the expression. 8x^-10 y^'6 -2x^2y^-8 Write your answer without negative exponents.​
sergij07 [2.7K]

Answer:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

Step-by-step explanation:

Given

8x^{-10}y^6 - 2x^2y^{-8}

Required

Simplify

Rewrite as:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}

Take LCM

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6*y^8 - 2x^2 * x^{10}}{x^{10}y^8}

Apply law of indices

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

8 0
3 years ago
How do I do it and be able to understand it
poizon [28]
Do what ? post for i can help you
3 0
2 years ago
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