<span> by taking integral we get
integral sec(x) (tan(x)+sec(x)) dx
applying integral we get
sec(x) (tan(x)+sec(x)) gives sec^2(x)+tan(x) sec(x)
= integral (sec^2(x)+tan(x) sec(x)) dx
Integrate the sum term by term
= integral sec^2(x) dx+ integral tan(x) sec(x) dx
For the integrand tan(x) sec(x), now we will use substitution
substitute u = sec(x) and du = tan(x) sec(x) dx
= integral 1 du+ integral sec^2(x) dx
The integral of sec^2(x) is tan(x)
= integral 1 du+tan(x)
The integral of 1 is u
= u+tan(x)+constant
Substitute the value of u which is equal to
= sec(x):
so our conclusion is
:tan(x)+sec(x)+constant
hope this helps</span>
Here is the answer. First change 20cm in mm = 200mm
ratio = 70mm/200
= 7 : 20
Hope this helps! Mark brainly please!
Answer:
The Answer is A.
Step-by-step explanation:
Please mark me brainliest.
So easy
so driscoll has 9 reports to grade and each page has 6 pages.
just multiply 9 and 6 which gives you your answer 54.
so out of 54, he has graded only 12 pages which means that you need to subtract.

driscoll has 42 pages left to grade.
you can recheck your answer by adding 42 ans 12 which gives your answer as 54. so yup our answer is right.