We can find the side length of square 3 by dividing by 4, which is 9.
Then, we find the side length of square 2 by dividing it by 4, which is 12.
To find the AREA of square 1, we do a^2+b^2=c^2. This is basically adding up area of square 1 and square 2 to get square 3.
a^2+b^2=c^2
9^2+12^2=c^2
81+144=225
So the area is 225 units.
To start, we're given the range that x lies in: from -1 to 4. We know from the fact that

that -1 will be <em /><em>included</em> in that range, so we mark -1 on the number line with a solid circle. We also know from

that, while x can be any value <em>up to</em> 4, it does not <em>include </em>4. We indicate this by drawing a hollow circle around 4 on the number line. Since x can be <em>any value within this range</em>, we make that fact clear by drawing a bold line between the points -1 and 4 on the number line. I've attached an image of what our final graph would look like.
Answer:
1/4*6/2=6/8
3/4
Step-by-step explanation: