This problem involves the use of a kinematic equation since it involves the motion of an object. The equation for the height of the object is given as:
s = -<span>16*t^2+v_o*t
Also, the initial velocity, v_o, was also said to be equal to 128 ft/s.
For the first question, </span><span>the time(s) that the projectile will reach a height of 240 ft when v_o is 128 feet per second, can be solved using the given equation and the quadratic formula. The resulting quadratic equation is then </span>-16*t^2 + 128*t -240 =0, where a =16, b =128, and c =-240. The quadratic formula is equal to [-b <span>± sqrt(b^2 -4ac)]/2a. This gives two answers t = 3 seconds and t = 5 seconds. This might be because the projectile has a parabolic path, thus, it reaches the height of 240 ft, before and after it reaches a peak.
For the second question, the time it takes for the projectile to reach the ground is obtained by setting the distance, s, equal to zero. In this case, t = 8 seconds.</span>
Answer:
528 dollars
Step-by-step explanation:
The starting price is $600. And it goes down by 20% then comes back up 10% so steps are:
First we got 20% off so I did 100 - 20 and got 80%
1: 80% * 600 = 80/100 * 600 = 480
Then we get an increase of 10% so I multiplied 110% with 480 which was our new price
2. 110/100 * 480 = 11 * 48(simplifying)
= 528
The slope is (8-2)/(0-2)=-3
the y intercept is 8
the equation is y=-3x+8
the area to the left is shaded, and the line is solid, so y
-3x+8
Answer:
1) n = 3.5
2) x = 4
Step-by-step explanation:
4 + 3 = 7 divide by 5 = 7/2
Answer:
20
Step-by-step explanation:
ones= 1
tens= 10
Hundreds= 100
The difference between ones and tens is the 0. ones=1. tens=10
<u>2</u>4
The 2 is in the beginning so its the 10's place. The 4 is the second number so its in the ones place
