Answer:
Yes
Step-by-step explanation:
Given,
Population mean Z = 600
Sample mean, µ = 586.50
Size of the sample, n = 10
Standard deviation, σ = 26.77
The testing hypothesis is,
Null hypothesis = µ<600
Alternative hypothesis = µ≥600
The test statistics is the calculated value of Z,
(Z- µ)/(σ/√n)
= (600-586.50)/(26.77/√10)
= (13.5*3.1623)/26.77
= 42.691/26.77
= 1.5947
And at 5% level of significance, the table value of Z = 1.644
Here, calculated Z<Table value of Z, so we accept the null hypothesis.
So, the null hypothesis is accepted. The mean value of the laptop is less than 600.
H/4=7/14
we cross multiply , so
14*h = 7*4
14h=28
divide by 14 on both sides
h=28/2=2
Take all the zero's away and multiply the numbers that are left.
which is 1*1=1 now add all of the zeros to that one which will turn it into
10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
which is the answer
Duration, time taken, the completion time
9514 1404 393
Answer:
382 square units
Step-by-step explanation:
The central four rectangles down the middle of the net are 9 units wide, and alternate between 8 and 7 units high. Then the area of those four rectangles is ...
9(8+7+8+7) = 270 . . . square units
The rectangles making up the two left and right "wings" of the net are 8 units high and 7 units wide, so have a total area of ...
2×(8)(7) = 112 . . . square units
Then the area of the figure computed from the net is ...
270 +112 = 382 . . . square units
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<em>Additional comment</em>
You can reject the first two answer choices immediately, because they are odd. Each face will have an area that is the product of integers, so will be an integer. There are two faces of each size, so <em>the total area of this figure must be an even number</em>.
You may recognize that the dimensions are 8, 8+1, 8-1. Then the area is roughly that of a cube with dimensions of 8: 6×8² = 384. If you use these values (8, 8+1, 8-1) in the area formula, you find the area is actually 384-2 = 382. That area formula is A = 2(LW +H(L+W)).
