Cables are forming 3 right angled triangles the pole being the shared height of them;
(height) b= 12yd
(base) a= 9yd
(hypotenuse) c= ?
Need to find the long side (hypotenuse);
a^2 + b^2 = c^2
12^2 + 9^2 = 225
Take square root of 225 = 15
Then you have;
1x 12yd = 12
3x 9 yd = 27
3x 15yd = 45
Add them up = 84yd of cable needed
Sqrt(2) = 1.41
so it would be between 1 and 2
Answer is A
Answer:
no
Step-by-step explanation:
<2=40° <11=60°
Because <1 was 140°, 2 is 40°. 40°+80°=120°
180°-120°=60°
