To write an equation in standard form, move each term to the left side of the equation and simplify.
ax2+bx+c = 0ax2+bx+c = 0
Move all the expressions to the left side of the equation.
−17−8x2−4x+3x2 = 0-17-8x2-4x+3x2 = 0
Add −8x2-8x2 and 3x23x2.
−17−5x2−4x = 0-17-5x2-4x = 0
Reorder the polynomial.
5x2+4x+17 = 0
Step-by-step explanation:
I hope this helped-
Answer:
-1 & -2
Step-by-step explanation:
x²+3x+2
x²+2x+x+2
(x²+2x)+(x+2)
x(x+2)+1(x+2)
(x+1)(x+2)
<span>Traveled Downstream a distance of 33 Mi and then came right back. If the speed of the current was 12 mph and the total trip took 3 hours and 40 minutes.
Let S = boat speed in still water then (s + 12) = downstream speed (s -12) = upstream speed
Given Time = 3 hours 40 minutes = 220 minutes = (220/60) h = (11/3) h Time = Distance/Speed
33/(s +12) + 33/(s-12) = 11/3 3{33(s-12) + 33(s +12)} = 11(s+12) (s -12) 99(s -12 + s + 12) = 11(</span> s^{2} + 12 s -12 s -144) 99(2 s) = 11(s^{2} -144) 198 s/11 = (s^{2} -144) 18 s = (s^{2} -144) (s^{2} - 18 s - 144) = 0 s^{2} - 24 s + 6 s -144 =0 s(s- 24) + 6(s -24) =0 (s -24) (s + 6) = 0 s -24 = 0, s + 6 =0 s = 24, s = -6 Answer) s = 24 mph is the average speed of the boat relative to the water.
The unit rate for that equation is .33
<h3>The alternate angles are equal, the co-interior angles are supplementary, and the corresponding angles are congruent.</h3>
