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Otrada [13]
2 years ago
8

For the following questions find the other half of the fraction.

Mathematics
1 answer:
valentina_108 [34]2 years ago
4 0

Answer:

<em>1</em><em>)</em><em> </em><em>3</em><em>/</em><em>5</em><em>=</em><em> </em><em>6</em><em>/</em><em>1</em><em>0</em>

<em>2</em><em>)</em><em> </em><em>3</em><em>/</em><em>6</em><em>=</em><em> </em><em>6</em><em>/</em><em>1</em><em>2</em>

<em>3</em><em>)</em><em> </em><em>4</em><em>/</em><em>1</em><em>0</em><em>=</em><em> </em><em>2</em><em>/</em><em>5</em>

<em>4</em><em>)</em><em> </em><em>3</em><em>/</em><em>4</em><em>=</em><em> </em><em>6</em><em>/</em><em>8</em>

<em>5</em><em>)</em><em> </em><em>5</em><em>/</em><em>1</em><em>0</em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em>

<em>6</em><em>)</em><em> </em><em>4</em><em>/</em><em>6</em><em>=</em><em> </em><em>8</em><em>/</em><em>1</em><em>2</em>

<em>7</em><em>)</em><em> </em><em>5</em><em>/</em><em>5</em><em>=</em><em> </em><em>1</em><em>0</em><em>/</em><em>1</em><em>0</em>

<em>8</em><em>)</em><em> </em><em>1</em><em>/</em><em>2</em><em>=</em><em> </em><em>6</em><em>/</em><em>1</em><em>2</em>

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Marcus has a square shaped garden that has an area of 4(x^2-y^2) square feet. If the garden has four equal sections, what is the
SpyIntel [72]

Answer:

x^2-y^2

Step-by-step explanation:

took a quiz and got it right

8 0
2 years ago
Need help with this.
stepan [7]
Third one down. you can tell just by the first two coordinates
6 0
2 years ago
Find the Area of the figure below, composed of an isoceles trapezoid and one
MAVERICK [17]

Answer:

the total area is 15.6 square units

Step-by-step explanation:

hello,

you can  find the total area  dividing the shape into two known shapes

total area= area of the trapezoid +area of the semicircle

then          

step one

find the area of the isosceles trapezoid using

A=\frac{a+b}{2}*h

where

a is the smaller base

b is the bigger base

h is theheight

A is the area

let

a=2

b=5

h=4

put the values into the equation

A=\frac{a+b}{2}*h\\A=\frac{5+2}{2}*4\\A=3.5*4\\A=14

Step two

find the area of the semicircle

the area of a circle is given by

A_{c}=\pi  \frac{d^{2}}{4}\\

but, we need the area of  half circle, we need divide this by 2

A_{semic}=\frac{ \pi \frac{d^{2}}{4}}{2}\\A_{semic}= \pi \frac{d^{2}}{8}

now the diameter of the semicircle is 2, put this value into the equation

A_{semic}= \pi \frac{2^{2}}{8}\\\\A_{semic}= \pi \frac{1}{2}\\ A_{semic}=\frac{\pi }{2}\\

find the total area

total area= area of the trapezoid +area of the semicircle

total\ area= 14+\frac{\pi }{2} \\total\ area=15.6

so, the total area is 15.6 square units

Have a good day.

5 0
3 years ago
Solve for a. 1/3(21-3a)=6-a
OverLord2011 [107]

Answer:

no solution

Step-by-step explanation:

Given

\frac{1}{3} (21 - 3a) = 6 - a ( multiply through by 3 to clear the fraction )

21 - 3a = 18 - 3a ( subtract 21 from both sides )

- 3a = - 3 - 3a ( add 3a to both sides )

0 = - 3 ← not possible

This indicates the equation has no solution

5 0
3 years ago
A principal gathered data about the distance in miles that his teachers and bus drivers live from the school
wel

Answer:

<em>The measure distances for the bus drivers is 5 miles less than that of distances for the teachers</em>

Step-by-step explanation:

<em>The range of the distance for the bus drivers live from school with that of the teachers is estimated to be 5 miles apart</em>

<em>The data that was generated in the school by the principal did an estimation of the distances of both the bus driver and that of the teachers, it was found out that the distances was five miles. </em>

4 0
3 years ago
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