Answer:
given
p=q^3
p=40
______
q=(p)^1/3
q=(40)^1/3-->q=2(5)^1/3
Now
the value of half of q , (2(5)^1/3)÷(2) ,is 5^1/3.
finally the value of p gonna be
p=q^3
p=(5^1/3) ^ 3
p=5
I'm pretty sure you would need to multiply 2/5 by 40.
So, if you multiply 2/5 by 40, you need to turn 40 into a fraction with 1 being the denominator.
2/5 x 40/1 = 80/5
Since the product is an improper fraction, you would simplify it to a whole number.
80/5 = 16.
He can expect to hit it 16 times to get a hole in one.
I hope I am right and have a great day.
The corresponding z score for speed of 62 mph, 47 mph, and 56 mph is 1.5, -2.25 and 0 respectively.
<h3>
Z score</h3>
Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

Where x is raw score, μ is mean, σ is standard deviation
Given that:
σ = 4, μ = 56, hence
for x = 62:

for x = 47:

for x = 56:

The corresponding z score for speed of 62 mph, 47 mph, and 56 mph is 1.5, -2.25 and 0 respectively.
Find out more on Z score at: brainly.com/question/25638875
<span>180>3x+24>90
-24 -24
156>3x>66
/3 /3 /3
52>x>22
possible values of x are any number greater than 22, but less than 52 </span>
The value of x is 4.
Given that diagonals of a rectangle measure x+5 feet and 2x+1 feet as shown in the attached figure.
The diagonal of a rectangle is a line or straight line that connects the opposite corners or vertices of the rectangle.
In the given figure ABCD is a rectangle.
OA=2x+1 and OD=x+5 [Given]
AC and BD are diagonals of a rectangle.
As we know that the diagonals of a rectangle are always equal.
So, AC = BD
We can also write it as,
2×OA=2×OD
2×(2x+1) =2×(x+5)
Apply the distributive property a(b+c)=ab+ac, we get
4x+2=2x+10
Subtract 2x from both sides, we get
4x+2-2x=2x+10-2x
2x+2=10
Subtract 2 from both sides, we get
2x+2-2=10-2
2x=8
Divide both sides by 2, we get
2x/x=8/2
x=4
Hence, the value of x=4 when diagonals of a rectangle measure x+5 feet and 2x+1 feet.
Learn more about rectangles from here brainly.com/question/1549055.
#SPJ4