Answer:
The technician should delete the startup configuration and the "vlan.dat" file residing in the flash memory of the newly added switch and lastly, he should reboot the switch.
Explanation:
In this scenario, a Cisco Catalyst switch has been added to support the use of multiple virtual local area networks (VLANs) as part of an enterprise network. The network technician finds it necessary to clear all virtual local area network (VLAN) information from the switch in order to incorporate a new network design. To accomplish this task successfully, the technician should delete the startup configuration and the "vlan.dat" file residing in the flash memory of the newly added switch and lastly, he should reboot the switch. The VLAN informations are stored in a file with the name "vlan.dat" residing in the flash memory of the switch.
However, in order to delete the startup configuration he would be required to login as an administrator, so as to have all privileges.
<em>Also, the essence of deleting the startup configuration and the "vlan.dat" is to avoid any conflict in the network. </em>
Answer:
Tbh i dont even know
Explanation:
I had who i wanted to become president but i don't even know anymore
Answer:
» Microsoft word ( word processing )
» Microsoft powerpoint ( presentation )
» Microsoft access ( database mamagement )
» Microsoft excel ( spread sheets )
Explanation:
Answer:
specific areas of access should be determined and they should be as restrictive as possible.
Explanation:
According to my research on security features of networks , I can say that based on the information provided within the question then specific areas of access should be determined and they should be as restrictive as possible. This would provide the highest level of security while still allowing production to be smooth.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
def sum_1k(M):
s = 0
for k in range(1, M+1):
s = s + 1.0/k
return s
def test_sum_1k():
expected_value = 1.0+1.0/2+1.0/3
computed_value = sum_1k(3)
if expected_value == computed_value:
print("Test is successful")
else:
print("Test is NOT successful")
test_sum_1k()
Explanation:
It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.
- Inside the <em>sum_1k(M)</em>, iterate from 1 to M and calculate-return the sum of the expression.
- Inside the <em>test_sum_1k(),</em> calculate the <em>expected_value,</em> refers to the value that is calculated by hand and <em>computed_value,</em> refers to the value that is the result of the <em>sum_1k(3). </em>Then, compare the values and print the appropriate message
- Call the <em>test_sum_1k()</em> to see the result
