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Law Incorporation [45]
2 years ago
10

This question pls I don’t understand

Mathematics
1 answer:
adell [148]2 years ago
5 0

Answer:

19.4

Step-by-step explanation:

50% is one half

so 9.7 is half of ....

Then .... is twice 9.7

.... = 2 × 9.7 = 19.4

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Use the given graph to determine the limit, if it exists.
Ahat [919]

The limit in the given graph \lim_{x \to \ 2^{-} } f(x) is 3 and \lim_{x \to \ 2^{+} } f(x) is -2

Given graph of a function and we have to determine the limits when x tends to 2 minus and when x tends to 2 plus.

When we see the graph we can find that the graph is not of the linear function because it is not straight line.

From x=2 and onwards it gives values values of only -2 because it is parallel to x-axis at y=-2.From x=2 and leftwards it gives values values of only 3 because it is parallel to x-axis at y=3.

Hence the limit of the function whose graph is shown is 3 and -2.

Learn more about limits at brainly.com/question/27517662

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8 0
2 years ago
An amount of $290000 is borrowed for a period of 25 years at an interest rate of 4%
Serhud [2]

Answer:

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Step-by-step explanation:

7 0
2 years ago
If the volume of a cube is 1000 ft.³ when is the service area
ExtremeBDS [4]

take the cube root of 1,000

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8 0
3 years ago
Read 2 more answers
Hello I need help Finding the probability
Stolb23 [73]
Each petal of the region R is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length 5\sqrt2, which implies the segment is subtended by an angle of \dfrac\pi2. This means the area of the segment is

\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}
\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2

This means the area of one petal is \dfrac{25\pi}2-25, and the area of R is four times this, or 50\pi-100.

Meanwhile, the area of G is simply the area of the square minus the area of R, or 10^2-(50\pi-100)=200-50\pi.

So

\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1
\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2
\mathbb P((X=R)\land(X=G))=0 (provided these regions are indeed disjoint; it's hard to tell from the picture)
\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1

4 0
3 years ago
Graph the given inequality.<br> y ≤ 4 – | x |
love history [14]

You'll get two X values because there is a modulus.

3 0
3 years ago
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