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Dafna11 [192]
3 years ago
6

Solve for x. Round to the nearest tenth, if necessary. 1.8 & x

Mathematics
1 answer:
Valentin [98]3 years ago
7 0

Answer:

x ≈ 1.4

Step-by-step explanation:

Using the sine ratio in the right triangle

sin50° = \frac{opposite}{hypotenuse} = \frac{RS}{RT} = \frac{x}{1.8} ( multiply both sides by 1.8 )

1.8 × sin50° = x , then

x ≈ 1.4 ( to the nearest tenth )

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Write 144 as a product of it's prime number. <br>plz faster,​
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Step-by-step explanation:

144 divided by 2 72

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3 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
An arithmetic sequence has a1 = 22 and a8 = 43. Find a15.
brilliants [131]

The 15th term of the arithmetic sequence a_{15} = 64

Option B is correct

The nth term of an arithmetic sequence is given as:

a_{n} = a + (n - 1)d

The first value, a = 22

a_8 = a+(8 - 1)d\\a_8 = a + 7d

Since a_8 = 43

43 = 22 + 7d\\7d = 43 - 22\\7d = 21\\d = \frac{21}{7}\\d = 3

The common difference, d = 3

a_{15}= a + (15-1)d\\a_{15} = a + 14d\\a_{15} = 22 + 14(3)\\a_{15} = 22 + 42\\a_{15} = 64

The 15th term of the arithmetic sequence = 64

Learn more here: brainly.com/question/24072079

4 0
2 years ago
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