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2 years ago

Mengapakah pandang darat fizikal pinggir laut di malaysia sesuai dijadikan kawasan pelancongan?

Geography

1 answer:

Novay_Z [31]2 years ago

6 0

Based on the question above, the answer goes thus:

Kerana Barat atau Semenanjung Malaysia terdiri daripada rangkaian hutan curam yang dilitupi pergunungan dengan dataran pantai di sebelah timur dan barat.

Selain itu, Malaysia Timur mempunyai dataran pantai berpaya yang luas yang naik ke bukit yang dilitupi hutan di pedalaman.

In conclusion, we can conclude that the correct answer is the alam semula jadi of the environment.

Learn more about Malaysia here: brainly.com/question/1049720

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In your own words, how do you describe Animism

Elodia [21]

Answer:

he belief, common among so-called primitive people, that objects and natural phenomena, such as rivers, rocks, and wind, are alive and have feelings and intentions. Animistic beliefs form the basis of many cults. ( See also fetish and totemism .)

Explanation:

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3 years ago

Which is made by weathering? minerals magma ash sediments

lana66690 [7]

Answer:

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3 years ago

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Northern america is home to______ percent of the world's population

dlinn [17]

Answer:

4.75%

Explanation:

Because North America has more people on Visa's and other things

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3 years ago

What is the value of X6? Show the solution.

wariber [46]

Answer : The value of $x_6$ is $\sqrt{7}$ .

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of $x_1$ .

Using Pythagoras theorem in triangle 1 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_1)^2=(1)^2+(1)^2$

$x_1=\sqrt{(1)^2+(1)^2}$

$x_1=\sqrt{2}$

Now we have to calculate the value of $x_2$ .

Using Pythagoras theorem in triangle 2 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_2)^2=(1)^2+(X_1)^2$

$(x_2)^2=(1)^2+(\sqrt{2})^2$

$x_2=\sqrt{(1)^2+(\sqrt{2})^2}$

$x_2=\sqrt{3}$

Now we have to calculate the value of $x_3$ .

Using Pythagoras theorem in triangle 3 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_3)^2=(1)^2+(X_2)^2$

$(x_3)^2=(1)^2+(\sqrt{3})^2$

$x_3=\sqrt{(1)^2+(\sqrt{3})^2}$

$x_3=\sqrt{4}$

Now we have to calculate the value of $x_4$ .

Using Pythagoras theorem in triangle 4 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_4)^2=(1)^2+(X_3)^2$

$(x_4)^2=(1)^2+(\sqrt{4})^2$

$x_4=\sqrt{(1)^2+(\sqrt{4})^2}$

$x_4=\sqrt{5}$

Now we have to calculate the value of $x_5$ .

Using Pythagoras theorem in triangle 5 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_5)^2=(1)^2+(X_4)^2$

$(x_5)^2=(1)^2+(\sqrt{5})^2$

$x_5=\sqrt{(1)^2+(\sqrt{5})^2}$

$x_5=\sqrt{6}$

Now we have to calculate the value of $x_6$ .

Using Pythagoras theorem in triangle 6 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_6)^2=(1)^2+(X_5)^2$

$(x_6)^2=(1)^2+(\sqrt{6})^2$

$x_6=\sqrt{(1)^2+(\sqrt{6})^2}$

$x_6=\sqrt{7}$

Therefore, the value of $x_6$ is $\sqrt{7}$ .

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3 years ago

A 163 square-kilometer (km2) small island is found 2,000km from the mainland. A second, larger, 230,000km2 island is found 1,000

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Answer:

4) The rate of species extinction is lower on the small island than on the large island.

Explanation:

The theory of island biogeography suggested that because of the size and links to the mainland. Fewer species that are not from the island will invade because the distance from the mainland is greater. The threat of extinction due to this is low. The small island also has a lower capacity for different species due to limited resources. This would mean that there are simply fewer species to go extinct.

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3 years ago

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