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Blababa [14]
3 years ago
6

PLEASEEEE HELP!DUE IN 1 HOUR! A housing contractor has subdivided a farm into 100 building lots. She has designed two types of h

omes for these lots: colonial and ranch style. A colonial requires $30,000 of capital and produces a profit of $3000 when sold. A ranch-style house requires $40,000 of capital and provides an $7000 profit. If the contractor has $3.8 million of capital on hand, how many houses of each type should she build for maximum profit?
Mathematics
1 answer:
Airida [17]3 years ago
3 0

Answer:

Step-by-step explanation:

A housing contractor has subdivided a farm into 100 building lots. She has designed two types of homes for these lots: colonial and ranch style. A colonial requires $30,000 of capital and produces a profit of $2000 when sold. A ranch-style house requires $40,000 of capital and provides an $8000 profit. If the contractor has $3.2 million of capital on hand, how many houses of each type should she build for maximum profit?

? colonials

? ranches

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The lower quartile of Class A is greater than the lower quartile of Class B.

Class A has a Greater number of lower quartiles then Class B as the imagie shows. Class A has 65-75 while class B has 70-75.

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An ice cream factory makes 230 quarts of ice cream in 5 hours. What is the constant of proportionality?
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Step-by-step explanation:

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3 years ago
Mr. Green teaches mathematics and his class recently finished a unit on statistics. The student scores on this unit are: 40 47 5
Harrizon [31]

Answer:

Mean = 64.46, Median = 62 and Mode = Bi-modal (50 and 62)

Range of the data is 55.

Step-by-step explanation:

We are given that Mr. Green teaches mathematics and his class recently finished a unit on statistics.

<u>The student scores on this unit are:</u>  40, 47, 50, 50, 50, 54, 56, 56, 60, 60, 62, 62, 62, 63, 65, 70, 70, 72, 76, 77, 80, 85, 85, 95.

We know that Measures of Central Tendency are: Mean, Median and Mode.

  • Mean is calculated as;

                   Mean  =  \frac{\sum X}{n}

where  \sum X = Sum of all values in the data

               n = Number of observations = 24

So, Mean  =  \frac{40+ 47+ 50+ 50+ 50+ 54+ 56+ 56+ 60 +60+ 62+ 62+ 62+ 63+ 65+ 70+ 70+ 72+ 76+ 77+ 80+ 85+ 85+ 95}{24}

=  \frac{1547}{24}  =  64.46

So, mean of data si 64.46.

For calculating Median, we have to observe that the number of observations (n) is even or odd, i.e.;

  • If n is odd, then the formula for calculating median is given by;

                     Median  =  (\frac{n+1}{2})^{th} \text{ obs.}

  • If n is even, then the formula for calculating median is given by;

                     Median  =  \frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.}   }{2}

Now here in our data, the number of observations is even, i.e. n = 24.

So, Median  =  \frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.}   }{2}

                    =  \frac{(\frac{24}{2})^{th}\text{ obs.} +(\frac{24}{2}+1)^{th}\text{ obs.}   }{2}

                    =  \frac{(12)^{th}\text{ obs.} +(13)^{th}\text{ obs.}   }{2}

                    =  \frac{62 + 62  }{2}  =  \frac{124}{2}  =  62

Hence, the median of the data is 62.

  • A Mode is a value that appears maximum number of times in our data.

In our data, there are two values which appear maximum number of times, i.e. 50 and 62 as these both appear maximum 3 times in the data.

This means our data is Bi-modal with 50 and 62.

  • The Range is calculated as the difference between the highest and lowest value in the data.

                      Range  =  Highest value - Lowest value

                                   =  95 - 40 = 55

Hence, range of the data is 55.

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Answer:

The terms equivalent to - 6 are

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