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Mrrafil [7]
2 years ago
15

Find the range or Y value for each of the given function domain or x values with the function. f(x)=-5x. f(1)=, f(2)=, f(3)=, f(

4)=.
Mathematics
1 answer:
Katena32 [7]2 years ago
8 0
You basically plug in the x values with the given function so the y values are -5,-10,-15,-20

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How do you substitute x+y=2 3x+2y=5
Monica [59]
Here's how you solve this.  So, x+y=2, right?  Let's isolate x.  x+y-y=2-y.  x=2-y.  NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y!  3x+2y=5.  3(2-y)+2y=5.  (3*2)+(3*-y)+2y=5.  6+(-3y)+2y=5.  6+(-y)=5.  6+(-y)-6=5-6.  -y=-1.  -y/-1=-1/-1.  y=1.

So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2.  x+1=2.  x+1-1=2-1.  x=1.  1+1=2, so that works; let's check the other equation.  3(1)+2(1)=5.  3+2=5.  5=5.  That's correct!

Answer: x=1, y=1
4 0
3 years ago
Read 2 more answers
Find the product of two numbers before multiplying by the next number. 25 × 3 × 2​
Varvara68 [4.7K]

Answer and explanation:

25 x 3 = 75

75 x 2 = 150

I found the product of the first two numbers, then multiplied the third.

The answer is 150. Hope this helps!

5 0
4 years ago
How many stickers can Kendall put in each bag
chubhunter [2.5K]
B. 1 and 5 are factors of all three numbers :)
5 0
4 years ago
What are the relative frequencies, to the nearest hundredth, of the rows of the two-way table?
sveta [45]

Answer:       A                 B

Group 1     0.25          0.75

Group 2    0.44          0.56

Step-by-step explanation:

Since we have given that

Number of people of A in group 1 = 15

Number of people of B in group 1 = 45

Total number of people in group 1 is given by

15+45=60

Relative frequency of people of A in Group 1 is given by

\frac{15}{60}=0.25

Relative frequency of people of B in Group 1 is given by

\frac{45}{60}=0.75

Similarly, Number of people of A in group 2 = 20

Number of people of B in group 2 = 25

Total number of people in group 2 is given by

20+25=45

Relative frequency of people of A in Group 2 is given by

\frac{20}{45}=0.44

Relative frequency of people of B in Group 2 is given by

\frac{25}{45}=0.56

Hence,        A                 B

Group 1     0.25          0.75

Group 2    0.44          0.56

6 0
3 years ago
10. Solve using substitution.<br> x - 2y = 3 3x + y = -5
nasty-shy [4]

Move all terms that don't contain x to the right side and solve.

x=−5/3−y/3

plz mark me as brainliest :)

5 0
3 years ago
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