Use the metric table to help answer the question.
2 answers:
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Answer:
See the explanation
Step-by-step explanation:
(a)
H0: Consultant with more experience has the higher population mean service rating.
H1: Consultant with more experience doesn't have the higher population mean service rating.
(b)
t = 1.9923 (see the attached image)
(c)
The degrees of freedom for the test statistic,
df = 16
The P-value of the one tailed t- test with 16 degrees of freedom is,
P−value = tdist(X,df,tails)
P-value = tdist(1.9923,16,1)
P-value = 0.032
(d)
Since, P-value 0.032 is less than the significance level 0.05, there is an enough evidence to reject the null hypothesis.
Hence, there is a sufficient evidence to conclude that Consultant with more experience doesn't have the higher population mean service rating.
Hope this helps!
Answer:
Step-by-step explanation:
Given that a machine produces defective parts with three different probabilities depending on its state of repair.
condition Good order Wearing down Needs main Total
Prob 0.8 0.1 0.1 1
Defective 0.02 0.1 0.3
Joint prob 0.016 0.01 0.03 0.056
a) 0.016
b) total = 0.056
c) If not defective from needs maintenance
Prob for not defective =
From machine that needs maintenance = 0.07
So reqd prob =