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yarga [219]
3 years ago
9

Some students paid a private tutor to help them improve their results on a certain mathematical test. These students had a mean

change in score of plus17 ​points, with a standard deviation of 67 points. In a random sample of 100 students who pay a private tutor to help them improve their​ results, what is the likelihood that the change in the sample mean score is less than 10​ points?
Mathematics
1 answer:
tatiyna3 years ago
7 0

Answer: Tt is unlikely to have change in the sample mean score is less than 10​ points .

Step-by-step explanation:

Given : Mean : \mu=17\text{ points}

Standard deviation : \sigma= 67\text{ points}

Sample size : n= 100

We assume that the change in students scores are normally distributed.

Let X be the random variable that represents the change in students scores .

Z score : z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

For x = 10

z=\dfrac{10-17}{\dfrac{67}{\sqrt{100}}}\approx-1.045

By using the standard normal distribution table , the probability  that the change in the sample mean score is less than 10​ points :-

P(X

Since the calculated probability is less than 0.5.

So , we say that it is unlikely to have change in the sample mean score is less than 10​ points .

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Step-by-step explanation:

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3 years ago
1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o
tester [92]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<u><em>A) If the length of a rectangle was tripled, but the  width did not change?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<u><em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

5 0
3 years ago
What is the x-coordinate of the solution to the following system of equations?
tatyana61 [14]

Answer

X-2y = 2

3x + y = 6

Ox=-2

Ox=0

Ox=2

Ox=3

= 0

Step-by-step explanation:

easy

8 0
3 years ago
Find the volume of a right circular cone that has a height of 11.4 in and a base with a radius of 5.1 in. Round your answer to t
ella [17]

Answer:

Step-by-step explanation:

h=11.4 in

r=5.1 in

v=3.14*r^2*(h/3)

V=3.14*5.1^2*(11.4/3)=3.14*26.01*3.8=310.35

5 0
3 years ago
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