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densk [106]
3 years ago
5

While Mrs. Poppington was visiting the historic battleground at Gettysburg, she

Mathematics
1 answer:
emmainna [20.7K]3 years ago
6 0

The new side lengths of the lawn would be: 2.5 inches, 0.75 inch, 1 inch and 1.5 inches.

<h3>Scale drawings</h3>

Scale drawing involves changing the size of a figure by dilating the figure.

There are two types of dilation

  • Enlarge
  • Compress

From the complete question, the dimensions of the lawn are:

10 yards, 3 yards, 4 yards, and 6 yards

Given that the scale factor is 1 inch to 1/4 yard

<h3>The new dimensions</h3>

The new dimensions of the lawn would be:

2.5 inches, 0.75 inch, 1 inch and 1.5 inches.

This is gotten by multiplying the original dimensions by the scale factor (1/4)

See attachment for the scale drawing

Read more about scale drawings at:

brainly.com/question/24579126

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Answer: x^2 - 13x + 13

Step-by-step explanation:


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3 years ago
2) f(x) = x² **<br> g(x)= 3x – 2<br> Find f(g(-4)
Usimov [2.4K]

Answer:

f(g( - 4)) = 196

Step-by-step explanation:

The functions are;

f(x) =  {x}^{2}

and

g(x) = 3x - 2

We want to find

f(g( - 4))

First we find g(-4) to get:

g( - 4) = 3 \times  - 4 - 2

g( - 4) =  - 12- 2

g( - 4) =  - 14

Now

f(g( - 4)) = f( - 14)

This implies that,

f(g( - 4)) = {( - 14)}^{2}

f(g( - 4)) = {( - 14)} \times  - 14

f(g( - 4)) = 196

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4 years ago
Round your answer to the nearest hundredth.<br> ?<br> А<br> C<br> 3<br> 70°<br> B
Anika [276]
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3 years ago
Explain why the "+ C" is not needed in the antiderivative when evaluating a definite integral.
Aliun [14]

The reason the "+ C" is not needed in the antiderivative when evaluating a definite integral is; The C's cancel each other out as desired.

<h3>How to represent Integrals?</h3>

Let us say we want to estimate the definite integral;

I = \int\limits^a_b {f'(x)} \, dx

Now, for any C, f(x) + C is an antiderivative of f′(x).

From fundamental theorem of Calculus, we can say that;

I = \int\limits^a_b {f'(x)} \, dx  = \phi(a) - \phi(b)

where Ф(x) is any antiderivative of f'(x). Thus, Ф(x) = f(x) + C would not work because the C's will cancel each other.

Read more about Integrals at; brainly.com/question/22008756

#SPJ1

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2 years ago
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