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Softa [21]
3 years ago
11

Find the smallest number that divides by 44 55 and 220 leaving remainder 5

Mathematics
1 answer:
galina1969 [7]3 years ago
8 0
The numbers from which we are to determine the smallest number that can be divided leaving a remainder of 5 are 44, 55, and 220. We have to do the prime factorization of all the numbers to determine their least common multiple (LCM).

Factorization of 44:
   44 = 11 x 4 = 11 x 2 x 2

Factorization of 55:
  55 = 11 x 5

Factorization of 220:
  220 = 11 x 20 = 11 x 5 x 4

Since 220 has all the factors from 55 and 44 then, the least common multiple is 220. Add 5 to the LCM in order to determine the unknown. 

<em>ANSWER: 225</em>
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You can solve as well getting same denominator for both fractions and comparing directly, in this case we need to get 2/3 to be divided by 30:
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