Find the smallest number that divides by 44 55 and 220 leaving remainder 5

1 answer:

galina1969 [7]2 years ago

8 0

The numbers from which we are to determine the smallest number that can be divided leaving a remainder of 5 are 44, 55, and 220. We have to do the prime factorization of all the numbers to determine their least common multiple (LCM).

Factorization of 44:
44 = 11 x 4 = 11 x 2 x 2

Factorization of 55:
55 = 11 x 5

Factorization of 220:
220 = 11 x 20 = 11 x 5 x 4

Since 220 has all the factors from 55 and 44 then, the least common multiple is 220. Add 5 to the LCM in order to determine the unknown.

ANSWER: 225

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