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Komok [63]
3 years ago
15

A train accelerates at an average rate of 0.33 meter per second squared, and the

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0

Answer:

I don't know

Step-by-step explanation:

please mark me as the brainlist

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What is the factored form of 30w+48
kotegsom [21]

Answer:

6\left(5w+8\right)

Step-by-step explanation:

30w+48

6\cdot \:5w+6\cdot \:8

6\left(5w+8\right)

4 0
3 years ago
I dont know what to do... im kinda not smart
myrzilka [38]

7.

10% = 6

25% = 15

50% = 30

20% = 12

_____________________

8.

a = 35

b = 105

c = 140

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9.

15 is 30% of 50.

_____________________________

10.

The punch recipe contains 25% lemonade:

24/6 = x/100

x=1/4 x 100 = 25%

_____________________________

11.

520

multiply 650 by 80 amd then divide by 100

or simply multiply 650 by 0.8

to get 520 students.

_______________________________________

12.

Number of items checked = 300

Defective items = 3%

Number of defective items =

Number of defective items =

Number of defective items = 9

Number of items worked = Total items - Number of defective items

Number of items worked = 300 - 9 = 291

291 items of checked items worked.

8 0
3 years ago
If g(x) = -8x+1. Find g(-2).
puteri [66]
-8*-2+1=16+1=17
g(-2)=17
7 0
3 years ago
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The values of w is inversely proportional to m .if w=8 then m=25; what is m when w=20?
iren2701 [21]

Answer:

m = 10

Step-by-step explanation:

Given w is inversely proportional to m then the equation relating them is

w = \frac{k}{m} ← k is the constant of variation

To find k use the condition w = 8, m = 25 , then

8 = \frac{k}{25} ( multiply both sides by 25 )

200 = k

w = \frac{200}{m} ← equation of variation

When w = 20 , then

20 = \frac{200}{m} ( multiply both sides by m )

20m = 200 ( divide both sides by 20 )

m = 10

3 0
3 years ago
The value of a collector’s item is expected to increase exponentially each year. The item is purchased for $500 and its value in
vekshin1

The item value after 4 years is $607.75 and could you put me as brainliest?

8 0
3 years ago
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