The perimeter of a rectangle is 90 cm the length is 27 cm what is the width of the rectangle
1 answer:
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Step-by-step explanation:
It is a little unclear when you state the problem what exactly is going on with that fraction. This is a common issue when you try to type up equations. On the right side, you have a fraction bar and then a bunch of stuff after it. We need to clear up what is supposed to be in the numerator and what is supposed to stay in the denominator. This is important not just for typing up questions on the internet to get help but in using your calculator as well. If what the equation means is that both "f" and "q+z" are in the denominator, but then on your calculator you type something 1 / 2 * f * ( q + z ), most calculators (e.g. TI 83/84 and almost any basic or scientific model) will interpret that as meaning only the 2 is on the bottom and the rest is on top.
If you meant the f and the q+z are on top, then Steve's answer is good.
If you meant the f and the q+z are supposed to be on the bottom, then we have a little bit different process.
First, write down the operations that are happening to q, and in what order they happen from inside out, that is, according to the regular PEMDAS rule:
1. z is added
2. 2f is multiplied
3. The result is divided into 1 (as opposed to being divided by 1).
So, to solve for q, we "invert" the order of operations and do the inverse operation of our 3 steps, and also in reverse order.
1. To get the big thing out of the denominator (Step 3), we will multiply both sides by 2f(q+z). Now we have:
C*2f(q+z) = 1, or as we normally write it,
2Cf(q+z) = 1
2. Now we have to adjust our steps just a little bit because we have the *C part too. So we will change Step 2 above to "2Cf is multiplied." We invert that by dividing, so we have:
q+z = 1/[2Cf]. Notice how I put brackets around the entire denominator so it's clear!
3. Finally to invert Step 1 we subtract z:
q = 1/[2Cf] - z
Given:
Line segment NY has endpoints N(-11, 5) and Y(3,-3).
To find:
The equation of the perpendicular bisector of NY.
Solution:
Midpoint point of NY is
Slope of lines NY is
Product of slopes of two perpendicular lines is -1. So,
The perpendicular bisector of NY passes through (-4,1) with slope . So, the equation of perpendicular bisector of NY is
Add 1 on both sides.
Therefore, the equation of perpendicular bisector of NY is .