Y=(x^4)-(6^3)+(50x^2)+122x=65find the zeros
1 answer:
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Answer:
(-5, -7) and the x-axis
Step-by-step explanation:
when looking for a point that is 7 points away, we are looking for a difference of 7 in either the x-value or the y-value.
[remember: a point is written as (x, y) ]
We know that the x-value is -7, meaning that it is 7 units under the x-axis (meaning that it is 7 units away)
We know that our point, (2 , -7) has the same y-value as (-5, -7), so we are looking for a change in x. The difference (which is the change) between:
-5 and 2 is 7
(2 - (-5) = 2 + 5 = 7)
so, both the x-axis and the point (-5, -7) are 7 units away from (2, -7)
(the other point (-7, 7) is not near (2 , -7) at all--they have a larger difference on both the y-values, the x-values, and the length of if you made a diagonal line)
(I've attached an image to help you visualize what we're doing)
hope this helps!!
