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Levart [38]
2 years ago
15

(Will Give Brainliest) −2(4

Mathematics
2 answers:
jok3333 [9.3K]2 years ago
4 0

Answer:

22

Steps:

2*(4+9)-5+1

= 2*(13)-5+1

= 2*13-5+1

= 26-5+1

= 21+1

= 22

mariarad [96]2 years ago
3 0

Answer: 16      

2^4

2*2*2*2

--> 16

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3 0
3 years ago
Helpppp Pleaseee....​
NeX [460]

Answer:

\frac{4 \sqrt{10} }{5}

Step-by-step explanation:

\frac{8}{ \sqrt{10} }  \times  \frac{ \sqrt{10} }{ \sqrt{10} }

\frac{8 \sqrt{10} }{ {\sqrt{10}}^{2}  }

\frac{8 \sqrt{10} }{10}

\frac{4 \sqrt{10} }{5}

3 0
3 years ago
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Because he always felt jumpy
4 0
3 years ago
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Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(
Stells [14]

Answer:

f(x) =  {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x  \rightarrow \: x = sec \: y\\  \frac{dx}{dx}  =  \frac{d(sec \: y)}{dx}  \\ 1 = \frac{d(sec \: y)}{dx} \times  \frac{dy}{dy}  \\ 1 = \frac{d(sec \: y)}{dy} \times  \frac{dy}{dx}  \\1 = tan \: y.sec \: y. \frac{dy}{dx}  \\ \frac{dy}{dx} =  \frac{1}{tan \: y.sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ \sqrt{( {sec}^{2}   \: y - 1}) .sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\   \therefore  \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx}  =  \frac{1}{ |5x |  \sqrt{25 {x }^{2}  - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} }

4 0
2 years ago
What is the answer for 1,296.5 × 10.2 ?
Elden [556K]
 the answer for 1296.5 times 10.2 is
13224.3

8 0
3 years ago
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