Answer:
Let X be the number of times the target is hit. The probability P(X≥1) then equals 1 minus the probability of missing the target three times:
P(X≥1) = 1− (1−P(A)) (1−P(B)) (1−P(C))
= 1−0.4*0.3*0.2
= 0.976
To find the probability P(X≥2) of hitting the target at least twice, you can consider two cases: either two people hit the target and one does not, or all people hit the target. We find:
P(X≥2)=(0.4*0.7*0.8)+(0.6*0.3*0.8)+(0.6*0.7*0.2)+(0.6*0.7*0.8) = 0.788
Step-by-step explanation:
To figure this out, you do 63 - 20 which is 43. I hope this helps!
Answer:
y = 12
Step-by-step explanation:
Looking at the large triangle
tan 30 = opposite / adjacent
tan 30 = 4 sqrt(3)/ y
Multiply each side by y
y tan 30 = 4 sqrt (3)
We know tan 30 = sqrt(3)/3
y * sqrt(3)/3 = 4 sqrt(3)
Multiply each side by 3/ sqrt(3) to isolate y
y * sqrt(3)/3 * 3/ sqrt(3) = 4 sqrt(3) * 3 /sqrt(3)
y = 12
Answer:im not sure but i thinkk its like this
Step-by-step explanation:
You use the distributive property so
4. 16
5. 18
in numbre six you multuply 6x5 and 5x5 then you add it and its 55
6.55
7.6
8.39
9.17
