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kondaur [170]
3 years ago
5

I’m revising a test, can someone please help me?

Mathematics
1 answer:
sergejj [24]3 years ago
3 0

Answer:

142°

Step-by-step explanation:

Sum of interior angles of a polygon= (n -2) ×180°, where n is the number of sides of the polygon

Since this polygon has 5 sides, n= 5.

Sum of interior angles

= (5 -2) ×180°

= 3 ×180°

= 540°

Sum of interior angles= 540°

5x +8+5x +10 +6x +15 +7x +2 +2x +5= 540

Grouping like terms together:

5x +5x +6x +7x +2x +8 +10 +15 +2 +5= 540

Simplify:

25x +40= 540

Bringing all constants to one side of the equation:

25x= 540 -40

25x= 500

Divide both sides by 25:

x= 500 ÷25

x= 20

The angle (7x +2)° is the largest interior angle in this polygon.

7x +2

= 7(20) +2

= 142

Thus, the largest interior angle is 142°.

<u>Check</u><u>:</u>

5x +8= 5(20) +8= 108

5x +10= 5(20) +10= 110

6x +15= 6(20) +15= 135

2x +5= 2(20) +5= 45

The other interior angles are 108°, 110°, 135° and 45°. Hence 142° is the largest interior angle in this polygon.

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(x + 5)(x - 4)(x + 2) =

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_________________________________

Compare :

{x}^{3}  + 3 {x}^{2}  - 18x - 40

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jasmine purchases shoes for $50. The store charges her 8% sales tax on the purchase. If jasmine gives the store owner $60, how m
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When will the equation p(b)=520(0.88)^b have a value less than 100?
yulyashka [42]

Answer:

The given equation will have value less than 100 whenever the value of b is greater than 12.89

Step-by-step explanation:

For the given equation, p(b) = 520 × 0.88^{b} to have a value less than 100 we can establish inequality as:

                     p(b) < 100

         or,  520 × 0.88^{b} < 100

         or, \frac{520}{520} × 0.88^{b} < \frac{100}{520}

         or, 0.88^{b} < \frac{1}{5.2}

         or, ㏒ ( 0.88^{b} ) < ㏒  (\frac{1}{5.2})

         or, b× ㏒ 0.88 < ㏒  (\frac{1}{5.2})

         or,  \frac{log (\frac{1}{5.2}) }{log (0.88)}   <  b

         or, 12.89 < b

Hence for the equation to have value less than 100, b must be greater than 12.89.

3 0
4 years ago
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