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sattari [20]
3 years ago
9

How many linear equations make up a system of linear equations?

Mathematics
1 answer:
pochemuha3 years ago
3 0
A system of linear equations is a set of two linear equations with two variables.
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Solve the given equation for x.<br> 7^4x-4 = 32
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4 0
3 years ago
Read 2 more answers
2x^2=9-3x <br> Find the factors
d1i1m1o1n [39]

Answer:

x = -3, $ \frac{3}{2} $

Step-by-step explanation:

The given quadratic equation is: $ 2x^2 = 9 - 3x $

This can be written as: $ 2x^2 + 3x - 9 = 0 $

To solve a quadratic equation of the form $ ax^2 + bx + c = 0 $ we use the formula:

           $ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$ x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)} $

$ \implies x = \frac{-3 \pm \sqrt{81}}{4} $

$ \implies x = \frac{-3 \pm 9}{4} $

We get two values of 'x', viz.,

x = $ \frac{-3 + 9}{4} $ and $ \frac{- 3 - 9}{4} $

$ \implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4} $

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $ \frac{3}{2} $) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $ \frac{3}{2} $ to see that this indeed is the given quadratic equation.

5 0
3 years ago
Emily purchased lemons for $600. She sold 3/4 of these at a loss of 20% and the remaining at a gain of 20%. How much percent doe
MAVERICK [17]

Answer:

10%

Step-by-step explanation:

Given: CP of lemon is $600.

           3/4 of lemon sold at 20% loss

           Remaining lemon at 20% gain.

Considering the quantity of lemon remain constant.

Cost price of 3/4 of lemon= \frac{3}{4} \times 600= \$450

As given, 3/4 of lemon sold at 20% loss.

∴ Selling price of \frac{3}{4}\ of\ lemon=  450- \frac{20}{100}\times 450

Selling price= 450- 90= \$ 360

Hence, selling price of 3/4 lemon is $360.

Now, the cost price of remaining lemon (1-\frac{3}{4} )= (\$ 600-\$ 450)

∴ The cost price of \frac{1}{4}\ lemon = \$ 150

As given, remaining \frac{1}{4} lemon\ sold\ at\ gain\ of\ 20\%

∴ Selling price of \frac{1}{4} \ lemon= (150\times \frac{20}{100}+150)

Selling price of \frac{1}{4} \ of\ lemon= (30+150)

Hence, selling price of 1/4 lemon is $180

Loss\profit percent= \frac{(SP-CP)}{CP} \times 100

∴ Loss\profit percent= \frac{60}{600} \times 100= 10\%

Hence, the loss percentage is 10%

8 0
3 years ago
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