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emmasim [6.3K]
3 years ago
6

there 7 adult adult chaperones and two third of the participants rode a large bus but if 54 people rode a large bus how students

went on a field trip
Mathematics
2 answers:
joja [24]3 years ago
8 0

54 x (2/3) = 36 students were on the bus.

54 - 36 = 18 chaperones were on the bus.

Hope this helps 

statuscvo [17]3 years ago
3 0

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~

54 * (2/3) = 36 students were on the bus.

54 - 36 = 18 chaperones were on the bus.

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Which set of ordered pairs represents a function?
laila [671]

Answer:

D

Step-by-step explanation:

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Solve for x <br><br><br><br><br><br>.problem down below ​
AleksAgata [21]
A: no solution!

first, simplify each side of the equation.

3x + 5 - 10x simplifies to -7x + 5.
8 - 7x - 12 simplifies to -7x - 4.

then, add +7x on both sides of the equation to get the variable alone. if you add 7x to each side, you get left with 0.

so, that leaves 5 = -4 which is not true. so, that means there is no solution.
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3 years ago
A cube has a volume of 216cm³ what is the side length of the cube​
ludmilkaskok [199]

Answer:

The side length of  the cube is 6 cm

Step-by-step explanation:

The volume of a cube is given by

V = s^3

We know the volume is 216

216 = s^3

Take the cube root of each side

216 ^ (1/3) = s^ (1/3)

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5 0
3 years ago
Read 2 more answers
Use the proportion. What is 72% of 150
kherson [118]

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108

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4 0
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Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
3 years ago
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