All categories

3 years ago

the graph of function f is shown. function g is represented in a table. which statement correctly compares the two functions?

Mathematics

1 answer:

daser333 [38]3 years ago

7 0

Answer:

Choice B

Step-by-step explanation:

Analysing both rhe graph and the table, we can see the functions f and g have a common point of (1,0), the x-intercept and same behaviour of reaching certain point of f or g, when the value of x gets closer to infinity.

This is matching the answer choice of B.

You might be interested in

What is one of the best methods to multiply these binomials: (x+8)(x+7)

Elodia [21]

The answer is C, you can do this by doing FOIL

3 0

2 years ago

Read 2 more answers

Fifteen equals s over thirteen

zimovet [89]

Can you restate the question please

6 0

3 years ago

Please helpp <br> 25 = (a - 29/10

dedylja [7]

Step-by-step explanation:

If you like my answer than please mark me brainliest and follow me thanks

3 0

3 years ago

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0

3 years ago

e) Isabel’s competition,who sells books and no other products, charges a shipping fee of $1.99 per book plus a fixed fee of $3 f

inessss [21]

Answer:

It will equal 0

7 0

2 years ago