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3 years ago

Do the ratios 1:9 and 4:6 form a proportion?

Mathematics

1 answer:

Umnica [9.8K]3 years ago

7 0

We have: $1:9=\frac{1}{9}=\frac{1.4}{9.4} =\frac{4}{36}=4:36\neq 4:6$

So the answer is: No

Ok done. Thank to me :>

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Damm [24]

Answer:

Step-by-step explanation:

We can tell that these pair of angles are corresponding, provided;

Line 1 ║ Line 2, AB ∩ Line 1 and Line 2 ⇒ corresponding ∠s ≅,

m∠ A = m∠ B ⇒ Substitute values of A and B,

6x + 12 = 3x + 63 ⇒ Subtract 3x on either side,

3x + 12 = 63 ⇒ Subtract 12 on either side of equation,

3x = 51 ⇒ Divide either side by 3,

<em>x = 17 </em>⇒ Substitute value of x to solve for m∠ A,

m∠ A = 6 * ( 17 ) + 12,

m∠ A = 102 + 12,

<em>Solution; x = 17°, m∠ A = 114°</em>

7 0

3 years ago

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Evaluate the expression using order of operations. 6 x 7 – 8 ÷ 4

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

6 x 7 = 42

8 ÷ 4 = 2

42 - 2

= 40

5 0

3 years ago

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For the polynomial below, -2 is a zero.

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

please note -2 is not a zero ,it should be 2 is a zero.

by synthetic division

2| 1 4 -10 -4

| 2 12 4

|----------------

1 6 2 | 0

x²+6x+2=0

$x=\frac{-6 \pm \sqrt{36-8} }{2} \\or~x=\frac{-6 \pm2\sqrt{7} }{2} \\or ~x=-3\pm \sqrt{7} \\h(x)=(x-2)(x^2+6x+2)=(x-2)(x-3+\sqrt{7} )(x-3-\sqrt{7})$

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3 years ago

Which graph represents the solution of x² + y² < 25 and y² <6x?

maxonik [38]

The graph is shown below

<h3>What is graph?</h3>

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

As, the equation x² + y² < 25 represents equation of circle.

So, the graph will be of the form circle.

and, y² <6x is the equation to represent parabola

So, the graph will represent a parabola.

Learn more about graph here:

brainly.com/question/16608196

#SPJ1

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2 years ago

If csc 0=8÷7 which equation represents cot 0

Dahasolnce [82]

Answer: $Cot\theta =\frac{\sqrt{15} }{7}$

Step-by-step explanation:

Since, given $cosec\theta=\frac{8 }{7}$

And we know that $Cot\theta=\sqrt{cosec^2\theta-1}$

Therefore, $Cot\theta=\sqrt{cosec^2\theta-1} = \sqrt{(8/7)^2-1}= \sqrt{64/49-1}$

⇒ $Cot\theta=\sqrt{64-49/49}=\sqrt{15/49}=\sqrt{15}/7$

Thus, $Cot\theta =\frac{\sqrt{15} }{7}$

4 0

4 years ago

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