All categories

3 years ago

Help on both please !!! don't give me irrelevant answers pls

Mathematics

1 answer:

Gennadij [26K]3 years ago

8 0

Answer:

< 1 is 85

X= 50

Step-by-step explanation:

ok the first question has 2 angles given 60 and 65

consider this one shows a 90 degree angle and the other does not. so 60 plus 90 equals 150 degrees

the u must say 65 plus x (x being angle 1) must also equal 150

subtract 65 from 150 and you get 85

now the second problem lets use the

Exterior Angle Theorem

The measure of an exterior angle (our w) of a triangle equals to the sum of the measures of the two remote interior angles (our x and y) of the triangle.

using this we know the 40 degree angle and 2x + 20 equals 3x plus 10

so we subtract 10 degrees from both sides and get

2x plus 10 plus 40 equals 3x now this means x equals 10 plus 40 which is 50

You might be interested in

What is 9.42 as a mixed number?

lord [1]

Answer:

9 $\frac{21}{50}$

That is the answer to the question

5 0

3 years ago

Read 2 more answers

4m-2+(-8m) Need answer ASAP please help me

DENIUS [597]

Answer:

-4m-2 Hope I helped

Step-by-step explanation: Remove parentheses.

4m−2−8m

Subtract 8m

from 4m

−4m−2

4 0

3 years ago

Read 2 more answers

Nick and June win some money and share it in the ratio 4:5. Nick gets £40. How much did June get?

sineoko [7]

Answer:

June gets $\£50$

Step-by-step explanation:

Let

x ----> amount of money Nick gets

y ----> amount of money June gets

we know that

$\frac{x}{y}=\frac{4}{5}$ -----> equation A

$x=40$ ----> equation B

solve the system by substitution

substitute equation B in equation A

$\frac{40}{y}=\frac{4}{5}$

solve for y

Multiply in cross

$(40)(5)=y(4)\\y=200/4$

$y=\£50$

8 0

4 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

In a class,14 out of 20 students pack their lunches.What percent of students pack their lunches?

svp [43]

Answer:

70%

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers