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Julli [10]
2 years ago
13

Mi

Mathematics
1 answer:
ddd [48]2 years ago
8 0

Answer:

Two buses leave towns 760 mi apart at the same time and travel toward each other. One bus travels

18 mi/h slower than the other. If they meet in

5 hours, what is the rate of each bus?

~~~~~~~~~~~~~~~~

Let x be the rate of the slower bus, in miles per hour.

Then the rate of the faster bus is (x+18) mph, according to the condition.

The slower bus covered 5x miles before the buses meet each other.

The faster bus covered 5*(x+18) miles before they meet each other.

The sum of distances covered by buses is 3x + 5*(x+18).

It is equal exactly 760 miles. It gives you an equation

5x + 5(x+18) = 760.

Simplify and solve for x:

5x + 5x + 90 = 760,

10x = 760 - 90,

10x = 670  ====>  x = 670%2F10 = 67.

Thus you found the rate of the slower bus. It is 67 miles per hour.

Then the rate of the faster bus is 67 + 18 = 85 mph.

Solved.

Step-by-step explanation:

Hope this helps :D

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The function f(x) = 200 × (1.098)x represents a village's population while it is growing at the rate of 9.8% per year.
AlexFokin [52]

The time for the village to dig the new well is about 7 1/2 years. At this time the population doubles from its current size.

<h3>How to graph a function?</h3>

For a function f(x) = y, the steps to draw a graph for the given function are as follows:

  • Consider certain values of x
  • Substitute x values in the given function to obtain y values
  • Plot the x and y values in the graph
  • Join the points to know the variation.

<h3>Calculation:</h3>

It is given that,

f(x) = 200 × (1.098)^x

Village's population growing rate = 9.8%

Creating a table for x and f(x) values:

x: 0   2   4   6   8   10

f(x = 0) = f(0) = 200 × (1.098)^0 = 200

f(x = 2) = f(2) = 200 × (1.098)^2 = 241

f(x = 4) = f(4) = 200 × (1.098)^4 = 291

f(x = 6) = f(6) = 200 × (1.098)^6 = 350

f(x = 8) = f(8) = 200 × (1.098)^8 = 423

f(x = 10) = f(10) = 200 × (1.098)^1^0 = 509

So,

(x, f(x)): (0, 200)  (2, 241)  (4, 291)  (6, 350)  (8, 423)  (10, 509)

Plotting these points in the graph and joining the points, the graph is shown below.

Finding the time for the village to dig a new well:

It is given that the population doubled from its current size, the village will need to dig new water well.

The current size of the village = 200

If it doubles for a certain time 't' = 400

So,

400 = 200 × (1.098)^t

⇒ (1.098)^t = 2

⇒ log(1.098)^t = log 2

⇒ t log(1.098) = 0.301

⇒ t × 0.04 = 0.301

∴ t = 7.525 years

Therefore, the village's population becomes double at the time 7 and half years from now. So, after 7 1/2 years, the village needs to dig a new well.

Learn more about the function and its graph here:

brainly.com/question/4025726

#SPJ1

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