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3 years ago

13

Pls answer quickly and include a lot of details

1 answer:

Viktor [21]3 years ago

7 0

18×10= dis is the answer ther is no equil heheheh

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The area of triangles and trapezoid

evablogger [386]

Shapes? We need to know how they look like in order to solve

7 0

3 years ago

A local country club has a membership of 600 and operates facilities that include an 18-hole championship golf course and 12 ten

shusha [124]

Answer:

0.45 = 45% probability that the member uses the golf course but not the tennis courts

Step-by-step explanation:

I am going to solve this question using the events as Venn sets.

I am going to say that:

Event A: Uses the golf courses.

Event B: Uses the tennis courts.

5% use neither of these facilities.

This means that $P(A \cup B) = 1 - 0.05 = 0.95$

75% use the golf course, 50% use the tennis courts

This means, respectively, by:

$P(A) = 0.75, P(B) = 0.5$

Probability that a member uses both:

This is $P(A \cap B)$ . We have that:

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

So

$P(A \cap B) = 0.75 + 0.5 - 0.95 = 0.3$

What is the probability that the member uses the golf course but not the tennis courts?

This is $P(A - B)$ , which is given by:

$P(A - B) = P(A) - P(A \cap B)$

So

$P(A - B) = 0.75 - 0.3 = 0.45$

0.45 = 45% probability that the member uses the golf course but not the tennis courts

3 0

3 years ago

How to do the bonus question

lbvjy [14]

Answer:

idkkkkkkkkkkkkk need more points

6 0

3 years ago

Pls help i will give brainliest

NeTakaya

Answer:

$2 \frac{5}{8} - 1 \frac{3}{8} = \frac{11}{8} = 1 \frac{3}{8}$

5 0

2 years ago

Read 2 more answers

Find the general solution of the following equation. Express the solution explicitly as a function of the independent variable.

Mashcka [7]

Answer:

Therefore the general solution is

$2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

Step-by-step explanation:

Integration Rule:

$\int x^n dx= \frac{x^{n+1}}{n+1}+c$
$\int \frac1x dx= ln(x) +c$

Given differential equation is

$x^2 \frac{dw}{dx}= \sqrt{w}(2x+5)$

$\Rightarrow x^2 dw= \sqrt{w} (2x+5) dx$ [ multiplying dx both sides]

$\Rightarrow \frac{dw}{\sqrt w}= \frac{(2x+5)}{x^2} dx$ [ dividing $x^2\sqrt w$ both sides]

Integrating both sides

$\int \frac{dw}{\sqrt w}=\int \frac{(2x+5)}{x^2} dx$

$\Rightarrow \int w^{-\frac12} dw=\int (\frac{2x}{x^2}+\frac{5}{x^2} )dx$

$\Rightarrow \int w^{-\frac12} dw=\int \frac{2}{x}dx +\int\frac{5}{x^2} dx$

$\Rightarrow \frac{w^{-\frac12+1}}{-\frac12+1} =2ln x+5 \frac{x^{-2+1}}{-2+1}+c$ [ c is arbitrary constant]

$\Rightarrow 2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

Therefore the general solution is

$2 \sqrt w = 2 ln(x) - 5 \frac1x +c$

6 0

3 years ago