3 years ago

Pls answer quickly and include a lot of details

Mathematics

1 answer:

Viktor [21]3 years ago

7 0

18×10= dis is the answer ther is no equil heheheh

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4 years ago

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The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasin

hoa [83]

Answer:

$\frac{dI}{dt}=-0.00016 A/s$

Step-by-step explanation:

We are given that

By ohm's law

$V=IR$

R=389 ohm

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$\frac{dR}{dt}=0.07ohm/s$

We have to find rate of change of current I means $\frac{dI}{dt}$

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$\frac{dV}{dt}=\frac{dI}{dt}R+I\frac{dR}{dt}$

Substitute the values then we get

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$-0.06=389\frac{dI}{dt}+0.0021$

$-0.06-0.0021=389\frac{dI}{dt}$

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Hence, the current I is changing at the rate=-0.00016A/s

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4 years ago

Convert the following into scientific notation:<br> 70.2 = _____ x 10 ____

ElenaW [278]

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Ostrovityanka [42]

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Answer:

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Step-by-step explanation:

breainliest really needed!!

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