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3 years ago

Help me do this work

Mathematics

1 answer:

siniylev [52]3 years ago

3 0

Answer:

question 3 - 23

Step-by-step explanation:

Question 3- add ten on both sides x=23

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62=−3k+7(k+6)+4<br><br> solve for k

guajiro [1.7K]

Step-by-step explanation:

62= -3k + 7k + 42 + 4

62 - 42 - 4 = 4k

16 = 4k

4 = k

7 0

3 years ago

Explain how comparing 645 and 738 is different from comparing 645 and 649

slavikrds [6]

I think it is because they are both different differences

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3 years ago

What is the domain of the relation?<br>

Tasya [4]

Answer:

D = { -4,-2,1,4}

Step-by-step explanation:

The domain is the inputs to the function

D = { -4,-2,1,4}

5 0

3 years ago

The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m

Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is $P(X=0) \approx 0.8659$

The probability of at least 1 failure in a 24-hour day is $P(X\geq 1 )\approx 0.3508$

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

$P(X)=\frac{e^{-\mu}\mu^x}{x!}$

Let X be the number of failures of a testing instrument.

We know that the mean $\mu = 0.018$ failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is $\mu=8\cdot 0.018=0.144$

$P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659$

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is $\mu=24\cdot 0.018=0.432$

$P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508$

3 0

3 years ago

Match each inequality with the number line that represents it.

algol13

in order

5 0

3 years ago