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makkiz [27]
3 years ago
5

The equation of line c is y–5=

Mathematics
2 answers:
Paraphin [41]3 years ago
8 0

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the "c" equation

y-5=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{3}{5}}(x-7)\qquad \impliedby \begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\\\cline{1-1}\\y-y_1=m(x-x_1)\\\\\cline{1-1}\end{array}

so line "d" is a line with a slope of 3/5 and passes through (1,-1)

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{3}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{3}{5}}(x-\stackrel{x_1}{1})\implies y+1=\cfrac{3}{5}(x-1) \\\\\\ y+1=\cfrac{3}{5}x-\cfrac{3}{5}\implies y=\cfrac{3}{5}x-\cfrac{3}{5}-1\implies y=\cfrac{3}{5}x-\cfrac{8}{5}

Fiesta28 [93]3 years ago
8 0

Answer:

y + 1 = (3/5)(x - 1)

Step-by-step explanation:

This is point-slope formula. It is super useful bc you can just fill in a point and the slope to make an equation of a line.

y - y = m(x - x)

Fill in the slope in place of the m.

Fill in the (x, y) given into the SECOND spot y and x .

Your equation had 3/5 in the m spot (that'sslope!) Swipe that and stick it in your equation.

Then they gave you a point (1, -1) that is the (x, y) you need to complete the equation.

The first y stays a y, dont fill in a number there. And the first x stays an x dont fill in a number there either.

Fill in second y, m and second x, and done! Its literally a fill in the blank question!

y + 1 = 3/5 (x - 1)

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Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2
ololo11 [35]

Answer:

The solution for given system of equation is: x=\frac{1}{5}\:and\:y=\frac{-9}{5} and ordered pair is: \mathbf{(\frac{1}{5},\frac{-9}{5})}

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

y=6x-3\\y=x-2

Solving:

Let:

y=6x-3--eq(1)\\y=x-2--eq(2)

Put value of y from equation 2 into equation 1

y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}

Now, put value of x in equation 2 to find value of y

y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}

So, the solution for given system of equation is: x=\frac{1}{5}\:and\:y=\frac{-9}{5} and ordered pair is: \mathbf{(\frac{1}{5},\frac{-9}{5})}

So, (1,3) is not solution to the given system of equations.

7 0
3 years ago
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