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4 years ago

I need an answer you guys !! Please

Mathematics

1 answer:

natka813 [3]4 years ago

3 0

First let's model the carpet as a rectangle.
The diagonal of a rectangle is given by:
d = root ((L) ^ 2 + (W) ^ 2)
Where,
L = long
W = width.
Clearing the width we have:
d = root ((L) ^ 2 + (W) ^ 2)
d ^ 2 = (L) ^ 2 + (W) ^ 2
(W) ^ 2 = (d) ^ 2- (L) ^ 2
W = root ((d) ^ 2- (L) ^ 2)
Substituting the values
W = root ((root (89)) ^ 2- (8) ^ 2) = 5
answer
The width of the carpet is
5 feet

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zmey [24]

Using the z-distribution, it is found that the 95% confidence interval for the mean lifetime of this type of drill, in holes drilled, is (10.4, 13.94).

We are given the <u>standard deviation for the population</u>, hence, the z-distribution is used. The parameters for the interval is:

Sample mean of $\overline{x} = 12.17$
Population standard deviation of $\sigma = 6.37$
Sample size of $n = 50$ .

The margin of error is:

$M = z\frac{\sigma}{\sqrt{n}}$

In which z is the critical value.

We have to find the critical value, which is z with a p-value of $\frac{1 + \alpha}{2}$ , in which $\alpha$ is the confidence level.

In this problem, $\alpha = 0.95$ , thus, z with a p-value of $\frac{1 + 0.95}{2} = 0.975$ , which means that it is z = 1.96.

Then:

$M = 1.96\frac{6.37}{\sqrt{50}} = 1.77$

The confidence interval is the <u>sample mean plus/minutes the margin of error</u>, hence:

$\overline{x} - M = 12.17 - 1.77 = 10.4$

$\overline{x} + M = 12.17 + 1.77 = 13.94$

The 95% confidence interval for the mean lifetime of this type of drill, in holes drilled, is (10.4, 13.94).

A similar problem is given at brainly.com/question/22596713

6 0

3 years ago

Time has a total of $28 after spending half of his weekly earnings on a video game and earning $10 additional dollars for mowing

Korolek [52]

Given:

Time has a total of $28 after spending half of his weekly earnings on a video game and earning $10 additional dollars for mowing the lawn.

To find:

Weekly earnings at his part time job.

Solution:

Let x be the weekly earning.

He spend half of his weekly earning, i.e., $\dfrac{x}{2}$

He earns $10 additional dollars for mowing the lawn.

According to the question,

$\dfrac{x}{2}+10=28$

$\dfrac{x}{2}=28-10$

$\dfrac{x}{2}=18$

Multiply both sides by 2.

$x=36$

Therefore, his weekly earnings is $36.

5 0

3 years ago

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emmasim [6.3K]

I think the answer is 23

8 0

3 years ago

Read 2 more answers

In a gambling game a person draws a single card from an ordinary 52-card playing deck. A person is paid $17 for drawing a jack o

Artyom0805 [142]

Answer:

$E.G=\$2$

Step-by-step explanation:

Sample size 52 card

Pay for J or Q $=\$17$

Pay for King or Ace $=\$5$

Pay for others $=-\$2$

Therefore

Probability of drawing J or Q

$P(J&Q)=\frac{8}{52}$

Probability or drawing King or Ace

$P(K or A)=\frac{8}{52}$

Probability or drawing Other cards

$P(O)=\frac{36}{52}$

Therefore

Expected Gain is mathematically given as

$E.G=\sum_xP(x)$

$E.G=17*\frac{8}{52}+5*\frac{8}{52}+(-2)*\frac{36}{52}$

$E.G=\$2$

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3 years ago

The average number of customers per day increased 25 percent during the sale. If the average number of customers per day before

Rasek [7]

Answer:

The average number of customers per day during the sale was 150.

Step-by-step explanation:

This question can be solved using a rule of three.

Before the sale, the average number of customers per day was 120, which is 100% = 1.

Now, there are x customers, and since it is an increase of 25%, it is 100+25 = 125% = 1.25. So

120 - 1

x - 1.25

x = 1.25*120 = 150

The average number of customers per day during the sale was 150.

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3 years ago