Question

Somebody help! How do I do this?​

Answer 1

Answer:

${ \tt{3y - 9 = { \blue{ \boxed{3}}(y) - { \blue{ \boxed{3}}(3)}}}} \\ \\ { \tt{3y - 9 = 3({ \blue{ \boxed{{ \tt{y}}}} - { \blue{ \boxed{3}})}}}}$

» 3y - 9 is equivalent to 3(y - 3)

Answer 2

Answer:

${ \tt{3y - 9 = { \blue{ \boxed{3}}(y) - { \blue{ \boxed{3}}(3)}}}} \\ \\ { \tt{3y - 9 = 3({ \blue{ \boxed{{ \tt{y}}}} - { \blue{ \boxed{3}})}}}}$

» 3y - 9 is equivalent to 3(y - 3)