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Leni [432]
2 years ago
5

Somebody help! How do I do this?​

Mathematics
2 answers:
Natalija [7]2 years ago
8 0

Answer:

{ \tt{3y - 9 = {  \blue{ \boxed{3}}(y) - { \blue{ \boxed{3}}(3)}}}} \\  \\ { \tt{3y - 9 = 3({ \blue{ \boxed{{ \tt{y}}}} - { \blue{ \boxed{3}})}}}} \\

» 3y - 9 is equivalent to 3(y - 3)

nlexa [21]2 years ago
4 0

Answer:

{ \tt{3y - 9 = {  \blue{ \boxed{3}}(y) - { \blue{ \boxed{3}}(3)}}}} \\  \\ { \tt{3y - 9 = 3({ \blue{ \boxed{{ \tt{y}}}} - { \blue{ \boxed{3}})}}}} \\

» 3y - 9 is equivalent to 3(y - 3)

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