2 years ago

Somebody help! How do I do this?

2 answers:

8 0

Answer:

${ \tt{3y - 9 = { \blue{ \boxed{3}}(y) - { \blue{ \boxed{3}}(3)}}}} \\ \\ { \tt{3y - 9 = 3({ \blue{ \boxed{{ \tt{y}}}} - { \blue{ \boxed{3}})}}}} \\$

» 3y - 9 is equivalent to 3(y - 3)

nlexa [21]2 years ago

4 0

Answer:

${ \tt{3y - 9 = { \blue{ \boxed{3}}(y) - { \blue{ \boxed{3}}(3)}}}} \\ \\ { \tt{3y - 9 = 3({ \blue{ \boxed{{ \tt{y}}}} - { \blue{ \boxed{3}})}}}} \\$

» 3y - 9 is equivalent to 3(y - 3)

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Somebody help! How do I do this?​