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kotykmax [81]
2 years ago
14

27. What is the value of x? own 52 48 X A 20 B 26 C 32 D 34 E 38

Mathematics
1 answer:
Artyom0805 [142]2 years ago
8 0

Answer is A

lmk if im wrong

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What is the equation of a parabola if the vertex is (1, 4) and the directrix is located at y = 7?
Oksana_A [137]

According to the vertex and the directrix of the given parabola, the equation is:

y = \frac{3}{4}(x - 1)^2 + 4

<h3>What is the equation of a parabola given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)^2 + k

In which a is the leading coefficient.

The directrix is at y = k + 4a.

In this problem, the vertex is (1,4), hence:

h = 1, k = 4

The directrix is at y = 7, hence:

4 + 4a = 7

a = \frac{3}{4}

Hence, the equation is:

y = a(x - h)^2 + k

y = \frac{3}{4}(x - 1)^2 + 4

More can be learned about the equation of a parabola at brainly.com/question/26144898

4 0
2 years ago
-8w + 3z when w = 2.2 and z = 9.1.
amm1812
The answer would be 9.7
4 0
3 years ago
Which of the following best represents the average speed of a fast runner?
Tpy6a [65]
For the answer to the question above, the easiest way to determine is changing every runner's speed into the same unit.

<span>First = 10 m/s </span>

<span>Second = 10 miles/min = 16090.34 / 60 m/s (As 1 mile = 1609.34 meter and 1 min = 60 sec) </span>
<span>Second = 260.82 m/s </span>

<span>Third = 10 cm/hr = 10*(0.01)/60*60 (As 1 cm = 0.01 m and 1 hr = 60*60 sec) </span>
<span>Third = 0.000028 m/s </span>

<span>Fourth = 10 km/sec = 10*1000 m/s (As 1 km = 1000 m and time is already in sec) </span>
<span>Fourth = 10000 m/s </span>

<span>So fastest would be the one who covers the largest distance in 1 sec. It would be the fourth one.</span>
3 0
3 years ago
Read 2 more answers
Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so
IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

<em><u>Solution:</u></em>

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

<em><u>Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars</u></em>

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

14 \times c + 5 \times v=119

14c + 5v = 119 ------- eqn 1

<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

10 \times c + 10 \times v = 130

10c + 10v = 130 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

<em><u>Substitute c = 6 in eqn 1</u></em>

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0
3 years ago
What does this mean!
DENIUS [597]
This is describing how your graph should be numbered. If I understand it, it is saying that your y-axis should be numbered by 2s while your x-axis should be numbered by 1s.

Below, I have attached an example graph that may help you understand.

8 0
3 years ago
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