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vesna_86 [32]
3 years ago
8

Help me with these equations

Mathematics
1 answer:
jenyasd209 [6]3 years ago
4 0

Answer:

8. \frac{8r^{2} }{q^{2} }

10. 12x^{-1} y^{6} z

Step-by-step explanation:

8. \frac{16p^{6}qr^{8}  }{2(p^{2}qr^{2})^{3}  } = \frac{16p^{6}qr^{8}  }{2p^{6}q^{3}r^{6}  }= \frac{8r^{2} }{q^{2} }

10. 4x^{2} y . 3 (-2x^{4} y)^{0} . x^{-3} y^{5} z = 4x^{2}y . 3(1) . \\x^{-3} y^{5}z = \\12x^{-1}yx^{6}z

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Determina la masa molar y el volumen que ocupa la siguiente sustancia CO2, si su masa es de 28 gr. *
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Answer:

Para el CO₂ sabemos que:

densidad = 0,001976 g/cm³

Sabemos que:

densidad = masa/volumen

Entonces, si tenemos una masa de 28 g, podemos escribir:

volumen = masa/densidad

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Para obtener la masa molar (es decir, la masa de un mol de esta sustancia) simplemente sumamos la masa de un mol de cada componente.

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Oxígeno: tiene una masa molar de 16 g/mol (y tenemos dos oxígenos)

entonces la masa molar va a ser:

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3 years ago
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