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vesna_86 [32]
3 years ago
8

Help me with these equations

Mathematics
1 answer:
jenyasd209 [6]3 years ago
4 0

Answer:

8. \frac{8r^{2} }{q^{2} }

10. 12x^{-1} y^{6} z

Step-by-step explanation:

8. \frac{16p^{6}qr^{8}  }{2(p^{2}qr^{2})^{3}  } = \frac{16p^{6}qr^{8}  }{2p^{6}q^{3}r^{6}  }= \frac{8r^{2} }{q^{2} }

10. 4x^{2} y . 3 (-2x^{4} y)^{0} . x^{-3} y^{5} z = 4x^{2}y . 3(1) . \\x^{-3} y^{5}z = \\12x^{-1}yx^{6}z

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Complete the table.<br> f(y) = 4y2 - 4v<br> f(v<br> -4<br> -3<br> -2<br> -1
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Step-by-step explanation:

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I will give barinest if solved
tankabanditka [31]

Answer:

x=19

Step-by-step explanation:

We\ are\ given\ that,\\Line\ YZ\ ||\ ZW\\\angle XYM=90\\Hence,\\Line\ Segment\ XY\ being\ the\ transversal,\ cuts\ YZ\ and\ XW.\\Hence,\\We\ know\ that\\The\ set\ of\ co-interior\ angles [Interior\ angles\ on\ the\ same\ side\\ of the\ transversal]\  are\ supplementary.\\Hence,\\Here,\\The\ pair\ of\ co-interior\ angles\ formed\ are\ \angle XYZ\ and\ \angle YXW.\\Hence,\ they\ are\ supplementary\ too.\\Hence,\\\angle XYZ\ + \angle YXW= 180\\Hence, by\ substituting\ XYZ=90+2x,\angle YXW=3x-590+2x+(3x-5)=180\\85+5x=180\\5x=180-85\\5x=95\\x=19

8 0
3 years ago
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