The kite is symmetric about line segment BD.
Therefore
AB = BC
3x + 1 = 22
3x = 22 - 1 = 21
x = 21/3 = 7
Similarly,
AD = CD by symmetry
Therefore
4x = CD
4*7 = CD
28 = CD, the required line segment
Answer: 28
First row, the answer on the left , -5 3/4 - 4 2/3
Answer:
w = (cv +dy) / (cb - ad)
Step-by-step explanation:
Multiply through by c
aw + y = c(bw + v) / d Multiply by d
d(aw + y) = c(bw + v) Remove the brackets
daw + dy = cbw + cv Subtract dy from both sides.
daw +dy - dy = cbw + cv -dy
daw = cbw + cv - dy Subtract cbw from both sides
daw - cbw = cbw - cbw + cv - dy
daw - cbw = cv - dy Isolate W on the left.
w(da - cb) = cv - dy Divide by cb - ad on both sides.
w = (cv - dy) / (ad - bc) Answer
Answer:
x = 6
y = 3
Step-by-step explanation:
Give triangle is a right triangle.
By applying sine ratio in the given triangle,
sin(60)° = 
x = 6
Now we take the cosine ratio in the given triangle,
cos(60)° = 
y = 
y = 
Therefore, x = 6 and y = 3 will be the answer.
Answer:
Step-by-step explanation:
1. The formula for distance=speed X time
18 X 2 X3600=129600km/s
