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4 years ago

What are the periodic trends in atomic radius select all that are correct?

Chemistry

1 answer:

lutik1710 [3]4 years ago

5 0

Actually we can see a lot of trends in the periodic table.

With regards to the atomic radius of the elements, going up to down there is an increasing pattern in the atomic radius.

While going left to right there is a decreasing pattern in the atomic radius.

Hence the smallest radius is on the upper right of the table.

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vekshin1

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600,000 square miles

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3 years ago

Determine the concentrations of BaBr2, Ba2 , and Br– in a solution prepared by dissolving 1.18 × 10–4 g BaBr2 in 1.00 L of water

Anika [276]

Supposing complete ionization:
BaBr2 → Ba{2+} + 2 Br{-} 

(2.23 × 10^–4 g BaBr2) / (297.135 g BaBr2/mol) / (2.00 L) = 3.75 × 10^-7 mol/L BaBr2 

(3.75 × 10^-7 mol/L BaBr2) x (1 mol Ba{2+} / 1 mol BaBr2) = 3.75 × 10^-7 mol/L Ba{2+} 

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3 years ago

What are the Sub atomic particles?

rusak2 [61]

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6 0

3 years ago

Given that Delta. G for the reaction below is –957. 9 kJ, what is Delta. Gf of H2O? 4NH3(g) 5O2(g) Right arrow. 4NO(g) 6H2O(g) D

vesna_86 [32]

ΔG for the formation of H₂O is -228.6 kJ.

<h3>How we calculate Gibb's free energy of the reaction?</h3>

Gibb's free energy of the reaction is calculated as:

ΔG = G for product - G for reactant

Given chemical reaction is:

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(g)

In the question, given that:

ΔG for the reaction = -957. 9 kJ

ΔGf of NH₃ = -16. 66 kJ/mol

ΔGf of NO = 86. 71 kJ/mol

Equation for ΔG will be written as:

ΔG = (ΔGf of NO + ΔGf of H₂O) - (ΔGf of NH₃+ ΔGf of O₂)

ΔGf of O₂ = 0

-957. 9 = (4×86. 71 + 6×ΔGf of H₂O) - (4×-16. 66 + 5×ΔGf of O₂)

-957. 9 = 346.84 + 6ΔGf of H₂O + 66.64

ΔGf of H₂O = (-957. 9 - 346.84 - 66.64) / 6

ΔGf of H₂O = -228.56 kJ ≅ -228.6 kJ

Hence, option (1) is correct i.e. -228.6 kJ is the ΔGf of H₂O.

To know more about Gibb's free energy, visit the below link:

brainly.com/question/14415025

6 0

3 years ago

How many moles of oxygen in 3.5 Mols of CH2O

o-na [289]

M of CH2O= 12+2+16=30 g/mol
So 30g/mol = 3.5 mol
=> 16g/mol*3.5 divide by 30 = 1.86 mol
I think

8 0

3 years ago