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tatuchka [14]
3 years ago
11

What is the equation of the line: * parallel to the line y = -¼x + 5 and * passing through the point (2, -1)

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0

Answer:

last one

Step-by-step explanation:

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Which graph represents the equation x = 3?
a_sh-v [17]

Answer:

Top graph

Step-by-step explanation:

x=3 is a vertical line where the value of x is always 3

4 0
3 years ago
Read 2 more answers
If f(x) = x² – 5, evaluate: f(x+h)-f(x)/<br> h
Likurg_2 [28]

The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.

<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>

In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:

f(x) = x² - 5                                         Given

f' = [(x + h)² - 5 - x² + 5] / h                Definition of derivative

(x² + 2 · x · h + h² - 5 - x² + 5) / h       Perfect square trinomial

(2 · x · h + h²) / h                                Associative, commutative and modulative properties / Existence of additive inverse

2 · x + h                                              Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse

2 · x                                                     h = 0 / Result

The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.

To learn more on derivatives: brainly.com/question/25324584

#SPJ1

6 0
2 years ago
What is the quotient?
Arturiano [62]
(3.78x109)<span>÷14,000
=0.02943
= 2.943 x 10^-2</span>
7 0
4 years ago
(1 - cos ß)(1 + cos ß) =1/cosec^2(ß)
iVinArrow [24]

Step-by-step explanation:

L.H.S=(1-cosB)(1+cosB)

=(1-cos^2B). {using (a+b) (a-b)=(a^2-b^2)in second step}

=sin^2B

=1/cosec^2B

Therefore,L.H.S=R.H.S proved

5 0
3 years ago
A: 1/2 inch <br> B: 1 inch <br> C: 2 inches<br> D: 1/32 inch
mote1985 [20]
The expression of the height is

a_n=8\cdot (\frac{1}{2})^{n-1}

the index "n" is the numbers of times that the ball is down, to n=1 the height is 8 inches, to n=2 the height is 4 inches.

An when n=5, the height is

a_5=8\cdot (\frac{1}{2})^{5-1}=8\cdot (\frac{1}{2})^4=\frac{1}{2} =0.5

the anwers is 0.5 inches
4 0
4 years ago
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