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vivado [14]
2 years ago
8

Which function(s)are decreasing on the interval

Mathematics
1 answer:
Amanda [17]2 years ago
5 0
Is there more to add onto this question?
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LM=9, NR=16, SR=8. Find the perimeter of △SMP.
Amanda [17]

Answer:

<h2>perimeter of △SMP = 25</h2>

Step-by-step explanation:

The perimeter of the triangle △SMP is the sum of al the sides of the triangle.

Perimeter of △SMP = ||MS|| + ||MP|| + ||SP||

Note that the triangle △LRN, △LSM, △MPN and △SRP are all scalene triangles showing that their sides are different.

Given LM=9, NR=16 and SR=8

NR = NP+PR

Since NP = PR

NR = NP+NP

NR =2NP

NP = NR/2 = 16/2

NP = 8

From △LSM,  NP = PR = <u>MS</u><u> = 8</u>

Also since LM = MN, MN = 9

From △SRP, SR = RP = <u>PS =  9</u>

Also SR =<u> MP = 8</u>

From the equation above, perimeter of △SMP = ||MS|| + ||MP|| + ||SP||

perimeter of △SMP = 8+8+9

perimeter of △SMP = 25

5 0
3 years ago
1. Writing an equation for an exponential function by
Naya [18.7K]

Answer: 1) t(n)=0.6(2)^n

2) f(x)=10(5)^x

Step-by-step explanation:

1) Let the function that shows the thickness of the paper after n folds,

t(n) = ab^n         ---------(1)

Since, According to the question,

Initially the thickness of the paper = 0.6

That is, at n = 0, t(0) = 0.6

By equation (1),

0.6 = a(b)^0\implies 0.6 = a

Hence the function that shows the given situation,

t(n) = 0.6 b^n       -----------(2)

Again when we fold the paper the thickness of the paper will be doubled.

Thus, at n = 1, t(1) = 1.2

By equation (2),

1.2 = 0.6 b^1\implies 2 = b

Thus, the complete function is,

t(n) = 0.6 (2)^n    

2) Let the function that is passing through the points (-2, 2/5) and (-1,2),

f(x) = ab^x         ---------(1)

For f(x) = 2, x = -1

By equation (1),

2= ab^{-1}       ---------(2)

Also, For f(x) = 2/5, x = -2

Again, By equation (1),

\frac{2}{5}= a(b)^{-2}

\implies \frac{2}{5}=ab^{-1}b^{-1}=2b^{-1}

\implies \frac{2}{5}=\frac{2}{b}

\implies 2b=10

\implies b = 5

By substituting this value in equation (2),

We get, a = 10

Hence, from equation (1), the function that is passing through the points (-2, 2/5) and (-1,2),

f(x) = 10(5)^x

5 0
2 years ago
Carl ran around the track 3 more times than Daria and 2 fewer times than Erin. When they were done they added up the number of l
Paul [167]

Answer:

Total laps = 10d

Step-by-step explanation:

Let c = Carl's laps

d = Daria's laps

e = Erin's laps

c = 3d

c = e/2

c + d + e = totals laps

We can insert 3d in place of c in the third equation

3d + d + e = total laps

Also, e/2 equals 3d

e/2 = 3d

Multiply both sides by 2

(e/2 = 3d)2

e = 6d

Insert the new e

3d + d + 6d = 10d = totals laps

3 0
2 years ago
What is the common ratio for geometric sequence: 5,15,45,135 ?​
serg [7]

Answer:

the common ratio is 3

Step-by-step explanation:

to solve for the common ratio, I like to take the second term and divide it by the first term

15/5 = 3

then I will check the rest of the terms

15*3 = 45

45*3 = 135

It looks like the common ratio is correct!

5 0
2 years ago
When patey pontoons issued 6% bonds on january 1, 2016, with a face amount of $600,000, the market yield for bonds of similar ri
GaryK [48]
You are given a bond interest of 6% that was given on January 1, 2016, with a face value of $600,000. Also, the market yield for bonds of similar risk, that <span>the market yield for bonds of similar risk and maturity was 7% and </span>the interest is paid semiannually on June 30 and December 31. You are to find the bond value on January 1, 2016. In here, because the yield of the market is above 6%, the bonds will have a discount for bonds less than $600,000.

Cash interest
= 0.06 * $600,000 * 6/12 (because it is done semiannually)
= $18,000
7%/2 = 3.5%

PV of interest at 3.5%
= $18,000 * 6.87396
= $123,731

PV of face at 3.5%
= $600,000 * 0.75941
= $455,646

Value of bond
= PV on interest + PV of face
= $123,731 + $455,646
= $579,377
3 0
2 years ago
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