1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Studentka2010 [4]
2 years ago
11

What values complete each statement? enter your answers in the boxes. (7√)2 = in simplest form. By the power of a power rule, (7

12)2=722. So, 712 must equal in radical form.
SAT
1 answer:
g100num [7]2 years ago
6 0

By the power rule, the radical expression become (7^{\frac{1}{2} })^2 = 7^{\frac{2}{2} }. Hence expressing 7^{\frac{1}{2} } as a radical is \sqrt{7}

<h3>Power rule in indices </h3>

Given the expression;

(\sqrt{7} )^2

This is expressed as;

(\sqrt{7})^2 = (7^{\frac{1}{2} })^2\\(\sqrt{7})^2 = 7^{\frac{1}{2} \times 2}\\(\sqrt{7})^2=7^1\\(\sqrt{7})^2 =7

By the power rule, the radical expression become (7^{\frac{1}{2} })^2 = 7^{\frac{2}{2} }. Hence expressing 7^{\frac{1}{2} } as a radical is \sqrt{7}

Learn more on radical function here: brainly.com/question/13430746

You might be interested in
A point charge q1 = -4. 00 nc is at the point x = 0. 60 m, y = 0. 80 m , and a second point charge q2 = +6. 00 nc is at the poin
Alekssandra [29.7K]

The net electric field is the vector sum of the components of the electric

field produced by the two charges.

The values of the magnitude and direction of the net electric field at the origin (approximate values) are;

  • 131.6 N/C
  • 12.6 ° above the negative x–axis

<h3>How are the net electric field magnitude and direction calculated?</h3>

The possible questions based on a similar question posted online are;

(a) The net electric field at the origin.

The electric field due to charge q₁ is given as follows;

\vec E_{1x} = \mathbf{ \dfrac{1}{4 \cdot \pi \cdot \epsilon_0} \cdot \dfrac{q_1}{\vec{r}^2_2}}

Which gives;

\vec{E}_{1x} =\mathbf{ \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot cos\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) =-21.6 \, N/C

\vec{E}_{1y} = \mathbf{\dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot sin\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) = 28.8 \, N/C

Which gives;

\vec{E}_1 = \mathbf{21.6 \, N/C  \cdot \hat x +  28.8 \, N/C \hat y}

\vec{E}_{2x} = \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(6.00 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2} = 150 \, N/C

Therefore;

\vec  {E} = \left[ 21.6 \, N/C - 150 \, N/C \right] \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)

\vec  {E} = \mathbf{\left( -128.4 \, N/C  \right) \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)}

The magnitude of the net electric field is therefore;

E = \sqrt{(-128.4^2 + 28.8^2)} ≈ 131.6

  • The magnitude of the net electric field at the origin is E ≈<u> 131.6 N/C</u>

(b) The direction of the net electric field at the origin.

  • The \ direction \ is \ arctan \left(\dfrac{28.8}{-128.4} \right) \approx \underline{ 12.6^{\circ}} \ above \ the \ negative \ x-axis

Learn more about electric field strength here:

brainly.com/question/14743939

brainly.com/question/3591946

3 0
2 years ago
N order to create imagery that appeals to the reader’s senses, an author must make careful word choices. Which words from the po
Fofino [41]

Answer:

luminous under the sand

Explanation:

I got it right on my Assignment :)

4 0
2 years ago
Read 2 more answers
So we recently had an options assembly for our IGCSE subjects/options and I realized that so far I’ve only picked 5 subjects whi
Minchanka [31]
Maybe some kind of math class :)
8 0
3 years ago
The two structures that limit transpiration are known as
Lady_Fox [76]
Leaf stomates are the primary sites of transpiration and consist of two guard cells that form a small pore on the surfaces of leaves. The guard cells control the opening and closing of the stomates in response to various environmental stimuli and can regulate the rate of transpiration to reduce water loss.
8 0
1 year ago
What is the volume of a cylinder with a height of 2 feet and a radius of 6 feet? use 3. 14 for pi. Enter your answer in the box.
musickatia [10]

Answer:

3.14 × 6^{2} × 2

Explanation:

Multiply 3.14 by 6 times 6 times 2

7 0
2 years ago
Other questions:
  • Name 3 life process that may have plateau periods
    7·2 answers
  • 4. It takes only a few drinks to raise your BAC to a level at which driving is illegal.
    5·2 answers
  • TEST URGENT NEED NOW I CAN POST ANOTHER ONE WITH A LOT OF points has anyone took this test it is an I just need o now if someone
    15·1 answer
  • Where is error in the following sentence ? The barber had three clients waiting; Larry, James, and Charles
    10·1 answer
  • History has decided that all people are completely determined by their genetics. True False
    8·2 answers
  • For a child categorized as having a slow to warm temperament as identified by Thomas and Chess, caregivers should...
    12·1 answer
  • Why am i here help me here
    5·1 answer
  • How many grams of aluminum are required to produce 3. 5 moles al2o3 in the presence of excess o2?.
    12·2 answers
  • Millington materials is a leading supplier of building equipment, building products, materials, and timber for sale, with over 2
    8·1 answer
  • This section consists of NINE (18) multiple-choice questions. Each question is worth one (1) mark. Read the below case study and
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!